Difference equations

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Difference equations

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need help with checking what I have
5 pages?

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yes! just want to check a couple and do one
do you know how to do #1...need to check it
http://www.aw-bc.com/ggts/ Ch.12 for reference
linear would be degree 1 that I am aware of but let me check the material
I have c as linear
c and d are both linear
d is not linear...
its got rationals in it that make it go haywire
ok right was seeing y sub n as exponent in denominator not just constant : (
gonna graph it...confused with homo and nonhom..have a and b as homo...had c too but changed
if you reform d it become 1 + y^2/2y and thats just a curvey mess
homo or nonhomo; you gotta pick all that apply? or just one?
all that apply -3 parts
the order is the difference beteen "n"s
a = 2nd order
b,c,d are all 1st orders
got that one...b-2 c- 1
b = n, n+1 .... a difference of 1; 1st order
ok gotcha
a = hom, its got a zero on the right hand side :)
understand that
looked at wrong checks only had a as homo just wanted to check that
i think only d is nonhomo
homogeneity aint my strength lol..... i guess you just need an eye for it.
don't understand other property other than =0 to make it hom...
LOL!
I have 2a need 2b
i'll try and figure2-4...how about 5 got 6 ...loved that one
you need 5?
i as trying to determine what a "complete" solution meant :)
yes
ok that is cool ; )
didn't want to weigh you down...
B(n+1) = ....
what level mathis this stuff anyways :)
B(n+1) = (.06)Bn - 25,000...so far
Precalculus...real-world
B(n+1) = (.06)Bn - 25,000(.03)n-1
pre calc real world eh...... you must be going to harvard or something lol
thats almost right in the equation...
i know right...UIUC in Illinois...sad part is 1-credit math module not even full course..smh
any idea how to get the 25000 to start at (times 1) :) Bn+1 = (.06)Bn - 25,000(.03)
B(n+1) = (.06)Bn - 25,000(1+.03).....
B(n+1) = (.06)Bn - 25,000 + 25,000(.03)^n something like this
B(n+1) = (.06)Bn -25,000(1.03)^(n-1)
http://www.docstoc.com/docs/18298713/Planning-for-retirement
i got it....im sure I do :)
its pretty much a loan in a loan....
at B0; n=0
n=1 lol....thats it :)
I got the balance increaseing at .06 each time; then subtract that 25000(+.03 for interest) for the next few years
you agree?
I'm pluggin in calc. and I'm missing something
B(n+1) = (.06)Bn -25,000(1.03)^(n-1) the first year we need a "0" to make that (1.03) = 1
\[B_{n+1}=(.06)B_{n} - 25000(1.03)^{n-1}\]
de we start this from n=0 or n=1?
got that let me keep trying
0
for the power we need n =1 so 1-1=0 and anything to 0 power is 1
correct
im writing it into a program :)
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neat....iterations inputed one at a time? not working
havent programed it ALL yet lol..let me give this a test run
getting warmer :)
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it should be 1.06 ...not .06
no....thats aint it ...
292, 250 for n=1
B+B(.06) = B(1.06)
Balance + 6% :)
293,000 should be it
300000(1.06)-25000 = 293000
this is it ;)
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forogt to change the "dressing" to 1.06 lol
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its good to go ;)
itll last 15 years :)
programming I can do ;)
html and javascript, we can do so much together :)
that is Awesome...learned a lilt programming-html but you are GREAT
taught meself that too ;)
never thought to use it...just the calc...thanks!
libraries shuttin down, good luck with the rest of it :)
ok thanks...what state are you in
florida ;)
Cool! just moved to IL from SC...ttyl

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