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need help with checking what I have

5 pages?

yes! just want to check a couple and do one

do you know how to do #1...need to check it

http://www.aw-bc.com/ggts/
Ch.12 for reference

linear would be degree 1 that I am aware of but let me check the material

I have c as linear

c and d are both linear

d is not linear...

its got rationals in it that make it go haywire

ok right was seeing y sub n as exponent in denominator not just constant : (

gonna graph it...confused with homo and nonhom..have a and b as homo...had c too but changed

if you reform d it become 1 + y^2/2y and thats just a curvey mess

homo or nonhomo; you gotta pick all that apply? or just one?

all that apply -3 parts

the order is the difference beteen "n"s

a = 2nd order

b,c,d are all 1st orders

got that one...b-2 c- 1

b = n, n+1 .... a difference of 1; 1st order

ok gotcha

a = hom, its got a zero on the right hand side :)

understand that

looked at wrong checks only had a as homo just wanted to check that

i think only d is nonhomo

homogeneity aint my strength lol..... i guess you just need an eye for it.

don't understand other property other than =0 to make it hom...

LOL!

I have 2a need 2b

i'll try and figure2-4...how about 5 got 6 ...loved that one

you need 5?

i as trying to determine what a "complete" solution meant :)

yes

ok that is cool ; )

didn't want to weigh you down...

B(n+1) = ....

what level mathis this stuff anyways :)

B(n+1) = (.06)Bn - 25,000...so far

Precalculus...real-world

B(n+1) = (.06)Bn - 25,000(.03)n-1

pre calc real world eh...... you must be going to harvard or something lol

thats almost right in the equation...

i know right...UIUC in Illinois...sad part is 1-credit math module not even full course..smh

any idea how to get the 25000 to start at (times 1) :)
Bn+1 = (.06)Bn - 25,000(.03)

B(n+1) = (.06)Bn - 25,000(1+.03).....

B(n+1) = (.06)Bn - 25,000 + 25,000(.03)^n something like this

B(n+1) = (.06)Bn -25,000(1.03)^(n-1)

http://www.docstoc.com/docs/18298713/Planning-for-retirement

i got it....im sure I do :)

its pretty much a loan in a loan....

at B0; n=0

n=1 lol....thats it :)

you agree?

I'm pluggin in calc. and I'm missing something

B(n+1) = (.06)Bn -25,000(1.03)^(n-1)
the first year we need a "0" to make that (1.03) = 1

\[B_{n+1}=(.06)B_{n} - 25000(1.03)^{n-1}\]

de we start this from n=0 or n=1?

got that let me keep trying

for the power we need n =1 so 1-1=0 and anything to 0 power is 1

correct

im writing it into a program :)

neat....iterations inputed one at a time? not working

havent programed it ALL yet lol..let me give this a test run

getting warmer :)

it should be 1.06 ...not .06

no....thats aint it ...

292, 250 for n=1

B+B(.06) = B(1.06)

Balance + 6% :)

293,000 should be it

300000(1.06)-25000 = 293000

this is it ;)

forogt to change the "dressing" to 1.06 lol

its good to go ;)

itll last 15 years :)

programming I can do ;)

html and javascript, we can do so much together :)

that is Awesome...learned a lilt programming-html but you are GREAT

taught meself that too ;)

never thought to use it...just the calc...thanks!

libraries shuttin down, good luck with the rest of it :)

ok thanks...what state are you in

florida ;)

Cool! just moved to IL from SC...ttyl