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anonymous

  • 5 years ago

Compute the derivative for f(x) = sin^2 xcos x

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  1. myininaya
    • 5 years ago
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    f'(x)=(sin^2x)'cosx+(cosx)'sin^2x

  2. anonymous
    • 5 years ago
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    product rule rules!

  3. myininaya
    • 5 years ago
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    who needs quotient when you have the product rule

  4. myininaya
    • 5 years ago
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    you can always rewrite a quotient as a product

  5. anonymous
    • 5 years ago
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    I don't have that as one of my answers in my homework. Is there any more breaking down or extra step?

  6. myininaya
    • 5 years ago
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    ' means you have to find the derivative

  7. myininaya
    • 5 years ago
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    i didnt do the whole problem for you

  8. myininaya
    • 5 years ago
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    i just gave u the first step

  9. myininaya
    • 5 years ago
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    what is (cosx)'=??

  10. myininaya
    • 5 years ago
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    what is (sin^2x)'=??

  11. myininaya
    • 5 years ago
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    fill in these blanks above

  12. dumbcow
    • 5 years ago
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    i think you missed an x f(x) = x*sin(x)^2*cos(x)

  13. myininaya
    • 5 years ago
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    I don't see an x up there?

  14. myininaya
    • 5 years ago
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    I see f(x)=(sinx)^2*cosx

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