A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Write (sin13+sin167+cos13+cos167)(sin13sin167+cos13cos167) in the form asinx. No calculators.
I used the calculator and got 0. But without it, I can't get the answer to equal 0. I'm up to: 4sin13cos13, which by the reduction formula, equals 4sin13sin77 but then what? ...
anonymous
 5 years ago
Write (sin13+sin167+cos13+cos167)(sin13sin167+cos13cos167) in the form asinx. No calculators. I used the calculator and got 0. But without it, I can't get the answer to equal 0. I'm up to: 4sin13cos13, which by the reduction formula, equals 4sin13sin77 but then what? ...

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh nevermind! there's the sinAcosB formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and sin^2A+cos^2A = 1 formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, that still doesn't get me 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0of course it does. expand and see.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I still don't get it.. what am I supposed to do with that formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure that the original expression is equal to zero?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh... that's rather stupid of me. i don't know how to use a calculator. i think i got it this time. by sinAcosB formula, it comes down to 2sin26, which equals the right answer.. this time. Thank you so much everyone!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.