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anonymous

  • 5 years ago

Use implicit differentiation to find dy/dx for y^2 = 2xy – x^2

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  1. anonymous
    • 5 years ago
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    best way to explain it is to treat y like a variable x .... which gets you: 2 y y'=2xy'+y-2x

  2. myininaya
    • 5 years ago
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    2yy'=2xy'+2y-2x

  3. myininaya
    • 5 years ago
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    Solve the above for y' and u are done

  4. anonymous
    • 5 years ago
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    yea that forgot some brackets

  5. anonymous
    • 5 years ago
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    is the 2yy 2y^2?

  6. myininaya
    • 5 years ago
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    ?I dont understand the question

  7. anonymous
    • 5 years ago
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    is the 2yy you wrote suposed to be 2y^2

  8. myininaya
    • 5 years ago
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    I think you are talking about 2yy' this does not equal 2yy

  9. anonymous
    • 5 years ago
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    okay I got 2y-2x

  10. myininaya
    • 5 years ago
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    do you know how to solve this equation for x: x+4=2x-3

  11. anonymous
    • 5 years ago
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    2yy'-2xy'=2y-2x y'(2y-2x)=2y-2x y'=1

  12. myininaya
    • 5 years ago
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    Eric is right

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