anonymous
  • anonymous
Use implicit differentiation to find dy/dx for y^2 = 2xy – x^2
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
best way to explain it is to treat y like a variable x .... which gets you: 2 y y'=2xy'+y-2x
myininaya
  • myininaya
2yy'=2xy'+2y-2x
myininaya
  • myininaya
Solve the above for y' and u are done

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anonymous
  • anonymous
yea that forgot some brackets
anonymous
  • anonymous
is the 2yy 2y^2?
myininaya
  • myininaya
?I dont understand the question
anonymous
  • anonymous
is the 2yy you wrote suposed to be 2y^2
myininaya
  • myininaya
I think you are talking about 2yy' this does not equal 2yy
anonymous
  • anonymous
okay I got 2y-2x
myininaya
  • myininaya
do you know how to solve this equation for x: x+4=2x-3
anonymous
  • anonymous
2yy'-2xy'=2y-2x y'(2y-2x)=2y-2x y'=1
myininaya
  • myininaya
Eric is right

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