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anonymous
 5 years ago
the algebraic expressions x2 divided by x² 9is undefined when x is ..?
anonymous
 5 years ago
the algebraic expressions x2 divided by x² 9is undefined when x is ..?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's undefined when the denominator is 0. This occurs when \[x^29=0 \rightarrow x=\pm 3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the denominator is zero than wouldnt the answer be zero?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, the denominator is zero for xvalues such that \[x^29=0\] By what you're saying, if the answer is zero, x=0. But then the denominator would be \[0^29=9\]which is fine. You can divide your expression by 9.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x2}{x^29}=\frac{something}{0}\]is undefined.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to find the xvalues that make the denominator 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it the 'undefined' thing, i.e. *why* you have to find x where x^29 = 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea.. i dont understand that..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. In division, you can't ever divide by 0. This is because, if we did it, we wouldn't actually end up with something that made sense. I'll give you a simple example.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're happy with\[\frac{6}{2}=3\] yeah?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if I then write,\[6=\left[ ? \right]\times 3\]what number would you put in there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if we imagine \[\frac{6}{0}=\left[ ? \right]\](i.e. *some* number)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6=0 \times \left[ ? \right]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What number would you put in now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We attempted to divide 6 by 0 and ended up with an IMPOSSIBILITY.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's why division by zero is undefined.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This will happen no matter what you try to divide by zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So that's why you have to find all the xvalues that will end up making x^29 = 0 ... because everything falls apart there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If x is 3 or 3, x^29 = 3^29 = 9  9 = 0 or x^29 = (3)^29 = 99=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x2}{x^29}=\frac{3 2}{3^29}=\frac{1}{0}\]when x=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x2}{x^29}=\frac{32}{(3)^29}=\frac{5}{0}\]when x=3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oooooooooooooh alrighttt tanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In both cases, you'll end up with the same rubbish you get with \[\frac{6}{0}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think it's clicked now :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Feel free to become a fan :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good luck with your algebra. Try and link it to numbers if you have trouble.
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