anonymous
  • anonymous
r=2/(5l)^-1/2 for L.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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myininaya
  • myininaya
I don't see L to solve for. Does l=L?
myininaya
  • myininaya
\[r=2/(\sqrt{5L})\]
myininaya
  • myininaya
is this right?

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More answers

myininaya
  • myininaya
\[r=2/(5L)^{-1/2}\]
myininaya
  • myininaya
which one is right?
anonymous
  • anonymous
\[ r= 2/(5L)^{-1/2}\]
myininaya
  • myininaya
ok
myininaya
  • myininaya
make that exponent positive by putting whatever the base of that exponent is in the numerator therefore making the exponent positive
myininaya
  • myininaya
like r=2(5L)^{1/2}
myininaya
  • myininaya
now divide by 2 giving u r/2=(5L)^(1/2)
myininaya
  • myininaya
to get rid of the square root square both sides giving you (r/2)^2=5L
myininaya
  • myininaya
Divide both sides by 5 giving you (1/5)*(r/2)^2=L
anonymous
  • anonymous
okay thanks
myininaya
  • myininaya
your welcome

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