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anonymous
 5 years ago
How is 10/(1+e^t) supposed to be integrated from limits 0 to 2? Please show steps.
anonymous
 5 years ago
How is 10/(1+e^t) supposed to be integrated from limits 0 to 2? Please show steps.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put 1 +e^t= z diff. w.r.t. z , we get e^t dt= dz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok lets do this way..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide the num and den. by e^t/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, w.r.t means with respect to.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I know you're trying to use substitution, but probably a different method from what I was taught

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What's the point of dividing num. and den. by e^t/2 though?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That was another method of doing it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I do not think dividing by E^t/2 is a correct step in integrating this though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do with the first method then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My problem is actually, I know that 1/(1+e^t) is lnl1+e^tl, but I don't know what to do with the 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Using substitution doesn't help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/(1+e^t) is lnl1+e^tl ???? how did u get that??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dhatraditya, do you have any input?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is integration....so I need to find antiderivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but ur retriceumption is false......1/(1+e^t) is lnl1+e^tl??? no way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what is the correct integration of 1/1+e^t; could you show me with steps?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first method works for sure......after putting 1+e^t=z u will get this : intergartion (dz/ (z1)z

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have yo change your limits appropriately

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is indefinite integral...therefore no lower n upper limits

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I actually don't care about the limits, I don't know how to antidifferentiate this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0zuuto: will u please substitue what I said.....this works ....I've just done it on paper

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0limits are 0 to 2 according to the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ankur is right, use substitution. It is the easiest method for definite integrals.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oooh. Is that chinese? Sorry I dont understand it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, my intention was to understand how to differentiate this, I'm trying it right now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It was a mistake to type it, it's japanese

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont forget to change the limits like dhatraditya said....u can't ignore them when u have integral in z

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can I make a suggestion? You might want to recognise\[\frac{1}{1+e^t}=\frac{1+e^te^t}{1+e^t}=\frac{1+e^t}{1+e^t}\frac{e^t}{1+e^t}=1\frac{e^t}{1+e^t}\]You can integrate that directly,\[t\log (1+e^t)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sub. in your limits and multiply by 10.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lokisan is right. His method is superior. and faster.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0coincidentally i just figured that out too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0making the integral into two parts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it becomes tlnle^t+1l I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but u need to get used to substitution as well....u can't just rely on making two integrals every time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Most cases substitution is required, but I'm not how substitution works in this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, substitution is a general method. Splitting was more elegant in this case and lokisan correctly spotted that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'd say now u have the answer ...try with subs. too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or yeah in the second part of the intergral where you have to integrate e^t/e^t=1, substitution works definitely

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now I just need to apply this to the problem, which was 10/1+e^t
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