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anonymous

  • 5 years ago

cell phone call costs $0.07 per minute for the first 25 minutes and $0.10 per minute for each additional minute.how much would a 47 minute call cost

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  1. anonymous
    • 5 years ago
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    47 minutes is broken down into 25 minutes + (47-25=22)minutes. The first 25 are charged at 7c/min for a total of 7 x 25 = 175c The next 22 minutes are charged at 10c/min for a total of 10 x 22 = 220c The total cost is therefore, (175 + 220)c = 395c which is $3.95

  2. anonymous
    • 5 years ago
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    0.07*25+0.10*(47-25)=1.75+2.2=3.95

  3. anonymous
    • 5 years ago
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    Peter is distributing pamphlets about dog care and samples of dog biscuits.The dog biscuits come in packages of 12 and the pamphlets are in paackages of 20.What is the smallest number of samples and pamphlets he needs to distribute without having any left over? How many packages of dog biscuits and pamphlets will peter need?

  4. anonymous
    • 5 years ago
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    Let the number of dog biscuit packages be D and the number of pamphlet packages, P. The number of dog biscuits distributed will then be 12D (12 biscuits per package times the number of packages) and the number of pamphlets will be 20P by similar reasoning. We want a situation where\[12D=20P\]since that means the number of dog biscuits distributed will equal the number of pamphlets. We can simplify that expression as\[3D=5P\]after dividing by a common factor of 4.

  5. anonymous
    • 5 years ago
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    Well, if D=5 and P=3, the equation will be equal.

  6. anonymous
    • 5 years ago
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    Also, for all integers D less than 5, we cannot find an integer for P that will make the statement true, so D=5 is the minimum we can have, and therefore, P=3 the minimum for pamphlet packages.

  7. anonymous
    • 5 years ago
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    5 dog biscuit packages; 3 pamphlet packages.

  8. anonymous
    • 5 years ago
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    How many packages of d and p will peter need though?

  9. anonymous
    • 5 years ago
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    ^^

  10. anonymous
    • 5 years ago
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    2

  11. anonymous
    • 5 years ago
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    No...I wrote it out...5 dog biscuit packages and 3 pamphlet packages.

  12. anonymous
    • 5 years ago
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    so 5 packages of dog biscuits and 3 packages of pamphlet packages?

  13. anonymous
    • 5 years ago
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    Yes...

  14. anonymous
    • 5 years ago
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    what is the smallest number of samples and pamphlets he needs to distribute without having any left over??????????

  15. anonymous
    • 5 years ago
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    He has to use 5 dog biscuit samples (each has 12 biscuits, which will mean he'll get through 60 biscuits) and 3 pamphlet packages (each has 20 pamphlets, which will mean he'll get through 60 pamphlets). 60 biscuits, 60 pamphlets = no waste.

  16. anonymous
    • 5 years ago
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    I dont understand????? Im confusedd

  17. anonymous
    • 5 years ago
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    Peter is distributing pamphlets about dog care and samples of dog biscuits.The dog biscuits come in packages of 12 and the pamphlets are in paackages of 20.What is the smallest number of samples and pamphlets he needs to distribute without having any left over? A:60 How many packages of dog biscuits and pamphlets will peter need? A: D=5, P=3.

  18. anonymous
    • 5 years ago
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    Thers a: And B: the a question is what is the smallest number of samples and pamphlets he needs to distribute without having any left over?????????? And the b problem is How many packages of dog biscuits and pamphlets will peter need?

  19. anonymous
    • 5 years ago
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    So can you write like a:=..... And b = ...........

  20. anonymous
    • 5 years ago
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    a) 60 b) 5 packages of dog biscuits, 3 packages of pamphlets.

  21. anonymous
    • 5 years ago
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    Ok thank you verryyyy much

  22. anonymous
    • 5 years ago
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    Okay, kenzielolo...you should become a fan after that!

  23. anonymous
    • 5 years ago
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    I will Thank you sorry i just did not understand it ? :)

  24. anonymous
    • 5 years ago
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    You don't have to apologize for not understanding something. That's why you came here :)

  25. anonymous
    • 5 years ago
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    yupp!!

  26. anonymous
    • 5 years ago
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    You should read through the explanation and try to learn it :)

  27. anonymous
    • 5 years ago
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    I struggle in math!

  28. anonymous
    • 5 years ago
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    But thank You soo Much!!

  29. anonymous
    • 5 years ago
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    For helping Me!

  30. anonymous
    • 5 years ago
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    It's no problem. You a fan yet..? ;p

  31. anonymous
    • 5 years ago
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    :D

  32. anonymous
    • 5 years ago
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    Thanks.

  33. anonymous
    • 5 years ago
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    welcomee

  34. anonymous
    • 5 years ago
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    Don't give up on math, even if it's hard...and come back if you need more help. Bye :)

  35. anonymous
    • 5 years ago
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    bye

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