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anonymous
 5 years ago
If I want to know what is 20200/e(0.07695)(16), how do I input the "e" in the calculator?
anonymous
 5 years ago
If I want to know what is 20200/e(0.07695)(16), how do I input the "e" in the calculator?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understand the e = ln but Im not getting the same anwer my instructors gets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem is A=pe^rt, where A=20200/e(0.076950(16) his answer is 5897.23

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The r =7.695% t= 16 years) or 16. I need help with finding e, please

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi, do you have any idea how to solve this?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0e is Euler's constant at about 2.71828. A good calculator should have it stored. It is the following limit: \[e = \lim_{n→∞}{(1+1/n)^n} = \sum_{n=0}^∞{\frac{1}{n!}}\]\[ = 1 + 1\left(1+\frac 1 2 \left(1 + \frac 1 3\left(1+\frac 1 4\left(1+\frac 1 5\left(1 + \cdots\right)\right)\right)\right)\right)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That looks like stats. Would the same be applied to basic algebra?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0It has nothing to do with statistics. Euler's constant is one of the most basic (next to π) constants of mathematics. It occurs very often, especially in analysis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That method is not getting me the same answer as my instructor

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Well, the only way I can get a nearly equal is by calculating \[\frac {20200}{1.08^{16}}\] But that is not really accurate if you are talking about interests. Then I would do \[\frac{20200}{1.07695^{16}} = 6169.11\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here's the entire question: what principal should be deposited at 7.695% to ensure the acct will be worth $20200 in 16 years. I have 2020/e(0.07695)(16)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The formula is A=pe^rt. Im not understanding "e" and its throwing my answer off. His answer is $5897.23

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In this case do you know how to calculate the e?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0That formula looks strange. Lets say initially you deposit a, and you have an interest rate of r = 7.695% = 0.07695 then after the first year you have your initial amount PLUS the interest: \[a_1 = a + r\cdot a = a\cdot (1 + r)\] and one year later the same is true based on a1. So after n years you get \[a_n = a\cdot(1+r)^{n}\] No e there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how he got $5897.23?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0I told you above. He rounded the interest rate to 8% and used the correct formula \[a = \frac{a_n}{(1+r)^n}\] at least that is the closest I can come to that solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In this case A = 20200/1+16?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.020200/(1+(0.07695)(16)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to use \(A = Pe^{rt}\) When doing continuously compounded interest. e is the base of the exponential function. You should have a button on your calculator for it (typically it's the same button as the LN button). And if not you can use an approximate value of 2.71828183
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