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anonymous
 5 years ago
having trouble trying to integrate sqrt (900300(t)sqrt 2+100t^2) from 0 to 3sqrt 2
anonymous
 5 years ago
having trouble trying to integrate sqrt (900300(t)sqrt 2+100t^2) from 0 to 3sqrt 2

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0does that sqrt go over the whole thing?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0k give me a sec let me think

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0do you know trig substitution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya but was having trouble tring to find the right thing to plug in

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0=int(sqrt(100)*sqrt(t^23sqrt(2)t+9) =int(10*sqrt(t^23sqrt(2)t+9/2+99/2) =int(10*sqrt([t3sqrt(2)/2)]^2+9/2) let tan pheta=[t3sqrt(2)/2]/[3/sqrt(2)] {3/sqrt(2)} *tan pheta=t3sqrt(2)/2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0{3/sqrt(2)}*sec^2(pheta) d(pheta)=dt so we have =int(10*(sqrt([9/2]tanpheta+9/2)*[3/sqrt(2)*sec^2pheta)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.010int(sqrt(9/2)*sqrt(tanpheta+1)*[3/(sqrt(2))]sec^2pheta) =10(3/sqrt(2))(3/sqrt(2))int(sqrt(sec^2pheta)sec^2pheta) =10(9/2)int(secpheta*sec^2pheta) =45int(sec^3pheta)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0should i go further? i havent done anything with the limits yet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0na i can do the limits

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i had to complete the square above just so you know
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