## anonymous 5 years ago how do I simplify this? (click to see problem)

1. anonymous

$2 \over 3\sqrt[3]{5}$

2. anonymous

One way to do it would be to move the 3 back into the radical then rasie the number to the power of 1/3 to remove the radical then change it to a negitive 1/3 to put it all on the top line then simplify

3. anonymous

hmm, you have to multiply the cubic 5 up and down ^_^:$=\frac{2.\sqrt[3]{5}}{3\sqrt[3]{5}.\sqrt[3]{5}}= \frac{2\sqrt[3]{5}}{15}$ Correct me if I'm wrong ^_^

4. anonymous

That's not quite right star, because it's a cubed root you'd have to multiply it 3 times. $\frac{2}{3\sqrt[3]{5}} = \frac{2}{3\sqrt[3]{5}} * \frac{\sqrt[3]{5}\sqrt[3]{5}}{\sqrt[3]{5}\sqrt[3]{5}} = \frac{2\sqrt[3]{25}}{15}$