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You have to find x such that\[10.8 \times 10^{12}=0.0012x^3-0.09x^2+1.5x+13\]

Have you learnt techniques for estimation?

Actually, it should be\[10.8=0.0012x^3-0.09x^2+1.5x+13\]

sortof im confused

Hang on, chai. I'll finish this first.

You'll see that this polynomial spits out 10.8 if x=-1.35, x=27.98, x=48.38.

Now, we're not going backward in time, so x=-1.35 can be discarded.

AH I see where I was messing up I didnt take out the 1.35

ok, well thank you .. wow its so easy to forget things that need to be eliminated

no probs...good luck :)

okay, im stay here

lol...ok

ok

This is the equation of your line, chai :)

OK