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anonymous

  • 5 years ago

what are the x-intercepts and mininum point(s) for the equation x^2+8x+16

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  1. anonymous
    • 5 years ago
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    Do you know how to factor?

  2. anonymous
    • 5 years ago
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    kinda

  3. anonymous
    • 5 years ago
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    That is how you find the x-intercepts. You are wanting factors of 16 that add to get 8 1 * 16 ? 2 * 8 ? 4 * 4? which one?

  4. anonymous
    • 5 years ago
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    4 and 4????

  5. anonymous
    • 5 years ago
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    Good so it factors into (x + 4)(x + 4)

  6. anonymous
    • 5 years ago
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    So you take each of those and solve for each of them = 0 x + 4 = 0 (since they are both the same you only do this once) x = -4 so this graph only touches the x-axis at -4

  7. anonymous
    • 5 years ago
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    If your x^2 term is positive then the graph opens upward and you have a minimum if your x^2 term is negative then the graph opens downward and you have a maximum

  8. anonymous
    • 5 years ago
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    Since the x^2 term is positive it opens upward... since it only crosses one time on the x-axis, it MUST be the minimum (-4,0)

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