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anonymous

  • 5 years ago

I need some help understanding clearing fractions. Example: -x+2/5=5-4/3x

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  1. anonymous
    • 5 years ago
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    -x+2/5=5-4/3x

  2. anonymous
    • 5 years ago
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    Is the equation a) \(-x + \frac{2}{5} = 5 - \frac{4}{3x}\) b) \(\frac{-x + 2}{5} = 5- \frac{4}{3x}\) c) None of the above.

  3. anonymous
    • 5 years ago
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    a)

  4. anonymous
    • 5 years ago
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    the x is not below the 4

  5. anonymous
    • 5 years ago
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    oh, good. That's even better.

  6. anonymous
    • 5 years ago
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    \[-x + \frac{2}{5} = 5 - \frac{4}{3}x\]

  7. anonymous
    • 5 years ago
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    Right?

  8. anonymous
    • 5 years ago
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    Yes

  9. anonymous
    • 5 years ago
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    Ok, so lets start by getting all of our 'like' terms to have the same denominator. To do that, we'll make the -x into a fraction with a 3 on bottom. How can we do that?

  10. anonymous
    • 5 years ago
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    -x/3

  11. anonymous
    • 5 years ago
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    Nearly, but it must maintain equivalence. 3/3 is 1 right?

  12. anonymous
    • 5 years ago
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    -1x/3

  13. anonymous
    • 5 years ago
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    No. Stop guessing and listen. 3/3 = 1. Right?

  14. anonymous
    • 5 years ago
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    yes

  15. anonymous
    • 5 years ago
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    Ok, and 1 times any number gives you the same number right? a*1 = a

  16. anonymous
    • 5 years ago
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    right

  17. anonymous
    • 5 years ago
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    so then: \[a = 1*a = \frac{3}{3}*a = \frac{3a}{3} = a\]

  18. anonymous
    • 5 years ago
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    Did you follow that? Sometimes it's hard to read on one line.

  19. anonymous
    • 5 years ago
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    yes

  20. anonymous
    • 5 years ago
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    Ok, so what is -x as a multiple of 1/3?

  21. anonymous
    • 5 years ago
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    The basic rule of thumb for equivalent fractions is: You can multiply the top and bottom by the same thing and the value doesn't change.

  22. anonymous
    • 5 years ago
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    don't know

  23. anonymous
    • 5 years ago
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    So we have: \[\frac{-x}{1}\] And we want to get a 3 on the bottom, so we multiply the bottom times 3. That means we have to multiply the top by 3 also to keep it having the same value as -x.

  24. anonymous
    • 5 years ago
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    \[\frac{-3x}{3} = -x\] Right?

  25. anonymous
    • 5 years ago
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    -3x/3

  26. anonymous
    • 5 years ago
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    Right.

  27. anonymous
    • 5 years ago
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    So lets do the same thing to the 5 on the right side of the equation. We need to get a 5 on bottom, so what would it be.. We have: \[\frac{5}{1}\]

  28. anonymous
    • 5 years ago
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    5/1+2/5

  29. anonymous
    • 5 years ago
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    Ok, we have this (after changing the denominator on -x) \[\frac{-3x}{3} + \frac{2}{5} = 5 -\frac{4x}{3}\]

  30. anonymous
    • 5 years ago
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    Can you use algebra to get all the terms with x on one side, and all the terms without x on the other?

  31. anonymous
    • 5 years ago
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    I appreciate you trying to help me, but I need to see the example I gave solved from the beginning to the end. It isn't working very well showing me a step here and there.

  32. anonymous
    • 5 years ago
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    Hello

  33. anonymous
    • 5 years ago
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    One second.

  34. anonymous
    • 5 years ago
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    Starting from \[\frac{-3x}{3} + \frac{2}{5} = 5 - \frac{4x}{3}\] Can you solve for x?

  35. anonymous
    • 5 years ago
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    James are you there?

  36. anonymous
    • 5 years ago
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    -x+2/5=5-4x/3

  37. anonymous
    • 5 years ago
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    Because you have denominators and an = sign, you need to find a common denominator. What is the common denominator using 5 and 3

  38. anonymous
    • 5 years ago
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    15

  39. anonymous
    • 5 years ago
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    So multiply the whole equation by 15.

  40. anonymous
    • 5 years ago
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    Yes.. every term.

  41. anonymous
    • 5 years ago
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    15(-x+2/5)=15(5-4/3x)

  42. anonymous
    • 5 years ago
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    Yep. And distribute.

  43. anonymous
    • 5 years ago
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    (15)(-x) + (15)(2) (15)(5) - (15)(4x) ----- = ------- 5 3

  44. anonymous
    • 5 years ago
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    Cancel out the denominators into the numerators.

  45. anonymous
    • 5 years ago
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    (15)(-x) + (3)(2) = (15)(5) - 5(4x)

  46. anonymous
    • 5 years ago
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    -15x + 6 = 75 - 20x

  47. anonymous
    • 5 years ago
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    Now solve for x in the usual way.

  48. anonymous
    • 5 years ago
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    Blexting, let him do it.

  49. anonymous
    • 5 years ago
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    I don't know

  50. anonymous
    • 5 years ago
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    James when you are solving and you see x's on both sides of the equation, I like to get rid of the smallest one. Which one is smaller -15x or -20x

  51. anonymous
    • 5 years ago
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    -20x

  52. anonymous
    • 5 years ago
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    so add 20x to both sides

  53. anonymous
    • 5 years ago
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    James, if you have an equation: 5x + 4 = 4 How do you solve for x?

  54. anonymous
    • 5 years ago
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    What do you get James when you +20x to both sides?

  55. anonymous
    • 5 years ago
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    20x-15x+6=75-20x=20X

  56. anonymous
    • 5 years ago
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    THE LAST ONE should be a plus sign

  57. anonymous
    • 5 years ago
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    Good so add like terms.

  58. anonymous
    • 5 years ago
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    -5x+6=75-x

  59. anonymous
    • 5 years ago
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    20x - 15x (20 - 15 = ?)

  60. anonymous
    • 5 years ago
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    -20x + 20x = (-20 + 20 = ?)

  61. anonymous
    • 5 years ago
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    5

  62. anonymous
    • 5 years ago
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    So you have 5x + 6 = 75 (because your -20 + 20 = 0 so you don't have any x's on that side)

  63. anonymous
    • 5 years ago
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    Then what?

  64. anonymous
    • 5 years ago
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    how do you get the x by itself.. do you get rid of the 5 first or the 6 first?

  65. anonymous
    • 5 years ago
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    5x=75-6

  66. anonymous
    • 5 years ago
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    Yes... but what is 75-6 5x = 69

  67. anonymous
    • 5 years ago
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    but isn't the answer suppose to be x=69/5 and how do you get that?

  68. anonymous
    • 5 years ago
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    Yes... divide in you calculator. 13.8

  69. anonymous
    • 5 years ago
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    where are you getting 13.8

  70. anonymous
    • 5 years ago
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    Once again, I appreciate the help, but I need to see the problem solved from beginning to end. It isn't helping trying to get me to figure out something I don't know. I have to see it work.

  71. anonymous
    • 5 years ago
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    would it be 5x-69 x=69÷5 x=69/5

  72. anonymous
    • 5 years ago
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    5x=69 x=69÷5 x=69/5

  73. anonymous
    • 5 years ago
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    Hello, is anybody there?

  74. anonymous
    • 5 years ago
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    I don't appreciate being ignored. Just because I don't understand doesn't mean I should not be helped. If I knew this crap I wouldn't be here in the first place. Thanks for nothing, and I will not recommend this place to anyone.

  75. anonymous
    • 5 years ago
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    James, nobody knows that you entered another comment on this page unless they are sitting here watching your post... You need to go and "ask a question" and someone will see it and respond...

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