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anonymous

  • 5 years ago

Which of the coordinate pairs below is a solution to the following system of equations? x2 + y2 = 157 x + y = 17

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  1. darthsid
    • 5 years ago
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    I believe the general way of solving these kinds of equations is to substitute the values of the coordinate pair for x and y in the equation, and see if the two sides match up. For example, if one of the given coordinate pairs is (2,5) Then, we will substitute x = 2, and y = 5. So, the equation will become: 2^2 + 5^2 = 157*2 + 5 = 17 29 = 319 = 17 This is obviously not true, so (2,5) is not the solution

  2. anonymous
    • 5 years ago
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    is it (3, 10)

  3. darthsid
    • 5 years ago
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    Try substituting x = 3 and y = 10 in your equation to find out!

  4. anonymous
    • 5 years ago
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    First of all you have two = signs in here... is that correct?

  5. anonymous
    • 5 years ago
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    yea

  6. anonymous
    • 5 years ago
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    Oh is it two equations. x^2 + y^2 = 157 AND x + y = 17

  7. anonymous
    • 5 years ago
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    yea

  8. anonymous
    • 5 years ago
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    Then the answer (x,y) will be where the x + y = 17 and the x^2 + y^2 = 17

  9. anonymous
    • 5 years ago
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    sorry x^2 + y^2 = 157

  10. anonymous
    • 5 years ago
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    is it (3,10)

  11. anonymous
    • 5 years ago
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    does 3 + 10 = 17

  12. anonymous
    • 5 years ago
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    no 30 Idk , i took a wild Guess of tha answer

  13. anonymous
    • 5 years ago
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    Oh.. I thought you had multiple choice.

  14. anonymous
    • 5 years ago
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    If you have to work it out... it is a bit of a long process... here we go.

  15. anonymous
    • 5 years ago
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    x + y = 17 y = 17 - x we substitute that into the other equation. x^2 + y^2 = 157 x^2 + (17-x)^2 = 157 x^2 + (17-x)(17-x) = 157 you foil the 17-x x^2 + 289 - 17x - 17x + x^2 = 157 2x^2 - 34x + 289 = 157 (add like terms) 2x^2 - 34x + 132 = 0 (make it = to 0) 2(x^2 - 17x + 66) = 0 take out gcf 2(x - 11)(x - 6) = 0 factor x - 11 = 0 or x - 6 = 0 x = 11 or x = 6 answers are (11,6) or (6,11)

  16. anonymous
    • 5 years ago
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    Actually is is (11,6) AND (6,11) you are intersecting a circle with a line.. That would be two points.

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