anonymous
  • anonymous
difference equations?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
amistre...hi
anonymous
  • anonymous
Step 1: What you want to do is drop the constant, the same as simply making the constant zero to get the homogeneous difference equation. Then you get a general solution to that homogenous difference equation. Step 2: Then go back and come up with a trial solution to the non-homogenous difference equation, the style of the trial solution being based on the kind of terms that are creating the non-homogeneous part (this will probably be the hardest part, so read that section of material carefully). Then put in particular values that you know solve the difference equation, specific values you got from working with the difference equation such as what xo is, what x1 is, allowing you to determine what the constants in your trial solution need to be. This gives you your particular solution. Step 3: As the last step you combine your general solution and your particular solution to get your complete solution for this specific problems, and of course verify that when applied it creates the correct values for x0, x1, .... xn. Overall you will have started with a "difference equation" expressing how to get x n+1 if you know x n, and you are ending with a formula that will calculate any x n by just knowing n. The formula allows you to calculate any x n term without working out all of the terms ahead of it.
anonymous
  • anonymous
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amistre64
  • amistre64
isnt this from yesterday :)
anonymous
  • anonymous
yes need clear understanding for solutions starting with 2b
anonymous
  • anonymous
I have 0,0 1, -1 2, -1.5 , 3 -1.75 4 -1.875, 5 -1.9375 6, -1.96875 for a
amistre64
  • amistre64
this is on 2a right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
you need to track these as community service hours ; )
anonymous
  • anonymous
add to resume
amistre64
  • amistre64
lol.... the problem or this session ;)
anonymous
  • anonymous
all of your time in OS
anonymous
  • anonymous
lol
anonymous
  • anonymous
just realized that was a joke, lol
amistre64
  • amistre64
homo diff is dropping the constant... :)
amistre64
  • amistre64
what does dropping the constant do for us?
anonymous
  • anonymous
gives us xsubn?
amistre64
  • amistre64
the good computers are all locked away today; this one hates openstudy. small font, no formating..... just awful
amistre64
  • amistre64
might go to McDs later and use the wifi.... if it aint busy/closed
anonymous
  • anonymous
yeah my laptop will not let me do anything in os anymore so have to sit at desktop
anonymous
  • anonymous
are you in school
amistre64
  • amistre64
so if we strip the constant; we are just left with: Xn+1 = (1/2)Xn which always equals itself, so I dont quite know why wed do that....
amistre64
  • amistre64
yeah, in the computer lab downstairs....
anonymous
  • anonymous
are you a student
amistre64
  • amistre64
yup
anonymous
  • anonymous
me to and unemployed since move
anonymous
  • anonymous
taught 8th grade Algebra back in SC
amistre64
  • amistre64
i cant get work since I hurt my back.
amistre64
  • amistre64
ima "liability"
anonymous
  • anonymous
oh no sorry to hear that...ever thought about starting online tutoring business..I can help you out
amistre64
  • amistre64
i thought about trying to do something like that; id be nice to have some sort of income other than PELL grant...
anonymous
  • anonymous
I'm studying off loans for now ; ( that is why I have to take this extra module that has nothing to do with my program of study...technically
anonymous
  • anonymous
send me your email address and I can send you a presentation I'm actually presenting on Tues. and the link to my website...I just started in March and have 3 students now but hope to advertise some more this summer...brishundra@yahoo.com
amistre64
  • amistre64
So the complete solution is jsut finding an equation that will sum up all the nth terms....
anonymous
  • anonymous
I have xn=(0.5)raised to n *C
anonymous
  • anonymous
keep looking back at table in a and messing me up bc different ?
amistre64
  • amistre64
couldnt we just solve for "Xn" and plug it in? maybe?...
amistre64
  • amistre64
y = .5(0) - 1 + .5(1) - 1 +.5(2)-1 + .5(3) -1 seems to be what they are getting at.
amistre64
  • amistre64
we can rearrange our equation to see it better: y - .5(0) + .5(1) + .5(n) - 1 - 1 - 1 - 1
amistre64
  • amistre64
we need ".5(n)" for any given interation of n right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
and we need -(1n) for every iteration of n right?
amistre64
  • amistre64
whatis: .5(n) - (n) = ?
anonymous
  • anonymous
the constant
amistre64
  • amistre64
at =1 we get -1.5 right?
amistre64
  • amistre64
at n=2 we get: .5(2) - (2) = -2.5 right?
amistre64
  • amistre64
-1.5 maybe, gonna have to see this on a calculator.... terrible font
anonymous
  • anonymous
ok
amistre64
  • amistre64
whats yout table in a look like?
anonymous
  • anonymous
0,0 1, -1, 2, -1.5 3, -1.75...
anonymous
  • anonymous
4 -1.875 5 -1.9375 6 -1.96875
amistre64
  • amistre64
i get from teh original stuff, not my stuff: 0; -1; -1.5; -1.75; -1.875...
anonymous
  • anonymous
I had that when I first started this , lol
anonymous
  • anonymous
but looked at xo=0 and thought I was wrong
amistre64
  • amistre64
your "key returns" arent formating; they look like this:
amistre64
  • amistre64
the value of X0 = 0 then it iterates from there
anonymous
  • anonymous
ok so 6 -1.984375
amistre64
  • amistre64
we get add ons of 1/2; 3/4; 7/8; 15/16; 31/32; 63/64; 127/128; 511/512
amistre64
  • amistre64
(2^n)-1 ------ 2^n
amistre64
  • amistre64
[(2^n)-1] -1 - -------- = y 2^n
amistre64
  • amistre64
thats our formula/equation for this bit lol
amistre64
  • amistre64
n=[1,inf]
amistre64
  • amistre64
it fits right?
amistre64
  • amistre64
the bottom of the fractions ar plugging away at 2^n; and the tops are following one step behind at (2^n)-1
amistre64
  • amistre64
X{n+1} = (1/2) X{n} 2X{x+1} = X{n} I got no idea how they supposed to do this and come up with that lol
amistre64
  • amistre64
X{n+1} 1 ----- = --- X{n} 2 <-- 2^n ? if we borrow that "n"
amistre64
  • amistre64
any ideas?
anonymous
  • anonymous
lost...trying something
amistre64
  • amistre64
I got the right equation; just dont know how to get it from their stuff....
anonymous
  • anonymous
is that for c
amistre64
  • amistre64
thats for ..... D i think
amistre64
  • amistre64
you got a link to the "look over this material" part of it?
amistre64
  • amistre64
The style of the trial solution being based on the kind of terms that are creating the non-homogeneous part (this will probably be the hardest part, so read that section of material carefully).
amistre64
  • amistre64
got 10 minutes til the college closes....
amistre64
  • amistre64
and StLeo is a catholic college so that ones closed for today as well; my internets are getting scarce :)
amistre64
  • amistre64
email me the "material" section: tony031172@gmail.com
anonymous
  • anonymous
ok THANKS a bunch!
anonymous
  • anonymous
http://www.aw-bc.com/ggts/

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