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The sum of five consecutive integers is 75. What is the third number? Please don't give me the answer right away....

Mathematics
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x+(x+1)+(x+2)+(x+3)+(x+4)=75
yes...Can you help me figure out the answer?
Artist, do you see how he arrived at that equation?

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Other answers:

Yes...I understand....
Ok, so how many x's do you have there on the left side.
five
Ok, so 5x. And what is the sum of the non-x's on the left side.
Protip: Use (x-2) + (x-1) + x + (x+1) + (x+2)
4....
4+3+2+1 is not 4.
sorry...10
Ok, so the left side is 5x + 10 , and that equals 75. What is x?
umm...18?
No. What are the steps to solving \[5x + 10 = 75\]
What do you do first?
Umm....multiplication, 5*x?
No. Isolate the x term, but subtracting 10 from both sides.
err by subtracting I mean.
ooh...okay...duh
Then divide both sides by 5 is the second step. What is x?
13?
Ok, so 13 is x is the first number, then what is the third number?
39...
no.
The sum of 5 sequential integers . The first integer is 13, what is the integer that comes after 13?
Duh,14...so the third number is 15?
Yes. Exactly.
13 + 14 + 15 + 16 + 17 = 75
Thank you...
Of course! =)
I fanned you! Can you fan me? you'll be my tenth fan!
Not that it matters much, but sure ;p
Thanks...It's kinda neat to have ten fans...
My method was cleaner *sad face*
Ooh...sorry....*sympathetic face*
I agree Newton, but ankur had already started in this vein, and it doesn't matter much either way, so long as the method is understood.
Yes...I agree...Maybe next time INewton....

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