anonymous
  • anonymous
Someone please help me real quick. Im going to post the question now
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
given \[\cos(\sqrt{t})/\sqrt{t}\] If l let u = sqt(t) then does that mean it applies to both cos funtion and root funtion, or just the inner most sqrt inside cos????????
anonymous
  • anonymous
both..........
anonymous
  • anonymous
that doesnt help me for taking the indefinite integral though

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anonymous
  • anonymous
because u have given new value to sqrt (t) no matter where it is
anonymous
  • anonymous
u might need to post your question to have opinions on that problem
anonymous
  • anonymous
\[\int\limits_{}^{}\cos(\sqrt{t})/\sqrt{t}\]
anonymous
  • anonymous
You need to consider \[\frac{\mathbb{d}u}{\mathbb{d}x} \]
anonymous
  • anonymous
/dt*
anonymous
  • anonymous
try sqrt(t)= z
anonymous
  • anonymous
I was trying to get ride of the root t in the botom with \[dt = 2\sqrt{t} du\]
anonymous
  • anonymous
You need to substitute in u for root t there aswell..
anonymous
  • anonymous
after substituting z=t^1/2 u give get as below integration sign ( cosz * 2z^2 dt )
anonymous
  • anonymous
then u can use integration by parts keeping z^2 as first term and cosz as second
anonymous
  • anonymous
let me show you what im trying
anonymous
  • anonymous
let u = \[\sqrt{t}\] then \[du = 1/(2\sqrt{t})dt\] \[dt = 2\sqrt{t}du\] then i get \[\int\limits_{}^{} \cos(u)/u 2\sqrt{t}du\]
anonymous
  • anonymous
is this wrong?
anonymous
  • anonymous
change t^1/2 to u because now we cant have t in new eqation, now we are dealing with u only
anonymous
  • anonymous
oooooooooooo
anonymous
  • anonymous
got it lol
anonymous
  • anonymous
u r on right track ..well done
anonymous
  • anonymous
bang !!! cheers!!! good luck with other problems too !!
anonymous
  • anonymous
thank you so much!
anonymous
  • anonymous
keep up the gud work !!!

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