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anonymous

  • 5 years ago

Someone please help me real quick. Im going to post the question now

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  1. anonymous
    • 5 years ago
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    given \[\cos(\sqrt{t})/\sqrt{t}\] If l let u = sqt(t) then does that mean it applies to both cos funtion and root funtion, or just the inner most sqrt inside cos????????

  2. anonymous
    • 5 years ago
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    both..........

  3. anonymous
    • 5 years ago
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    that doesnt help me for taking the indefinite integral though

  4. anonymous
    • 5 years ago
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    because u have given new value to sqrt (t) no matter where it is

  5. anonymous
    • 5 years ago
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    u might need to post your question to have opinions on that problem

  6. anonymous
    • 5 years ago
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    \[\int\limits_{}^{}\cos(\sqrt{t})/\sqrt{t}\]

  7. anonymous
    • 5 years ago
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    You need to consider \[\frac{\mathbb{d}u}{\mathbb{d}x} \]

  8. anonymous
    • 5 years ago
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    /dt*

  9. anonymous
    • 5 years ago
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    try sqrt(t)= z

  10. anonymous
    • 5 years ago
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    I was trying to get ride of the root t in the botom with \[dt = 2\sqrt{t} du\]

  11. anonymous
    • 5 years ago
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    You need to substitute in u for root t there aswell..

  12. anonymous
    • 5 years ago
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    after substituting z=t^1/2 u give get as below integration sign ( cosz * 2z^2 dt )

  13. anonymous
    • 5 years ago
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    then u can use integration by parts keeping z^2 as first term and cosz as second

  14. anonymous
    • 5 years ago
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    let me show you what im trying

  15. anonymous
    • 5 years ago
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    let u = \[\sqrt{t}\] then \[du = 1/(2\sqrt{t})dt\] \[dt = 2\sqrt{t}du\] then i get \[\int\limits_{}^{} \cos(u)/u 2\sqrt{t}du\]

  16. anonymous
    • 5 years ago
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    is this wrong?

  17. anonymous
    • 5 years ago
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    change t^1/2 to u because now we cant have t in new eqation, now we are dealing with u only

  18. anonymous
    • 5 years ago
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    oooooooooooo

  19. anonymous
    • 5 years ago
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    got it lol

  20. anonymous
    • 5 years ago
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    u r on right track ..well done

  21. anonymous
    • 5 years ago
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    bang !!! cheers!!! good luck with other problems too !!

  22. anonymous
    • 5 years ago
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    thank you so much!

  23. anonymous
    • 5 years ago
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    keep up the gud work !!!

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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