anonymous
  • anonymous
need a refresher solve the equations by graphing 3x+y=15 4x+5y=9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
To solve by graphing means graph each equation and see where they intersect.
anonymous
  • anonymous
Do you know how to graph these?
anonymous
  • anonymous
multiply first by 4 and second by 3 and subtract to eliminate x

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anonymous
  • anonymous
or multiply first by 5 and subtract from 2 to eliminate y
anonymous
  • anonymous
ahhhhh......we r graphing.....damn
anonymous
  • anonymous
give two values to x and y in the first equation to draw the line for first equation
anonymous
  • anonymous
same with the second one.
anonymous
  • anonymous
and check where it intersects !!
anonymous
  • anonymous
so lets say (4,3) for the first equation
anonymous
  • anonymous
The easiest way to graph a line is to find the intercepts by plugging in 0 for x, and solve for y, then plug in 0 for y and solve for x. That will give you two points \((0,y_0)\) and \((x_0,0)\). Then you just draw the line that connects them and that is the graph of the equation.
anonymous
  • anonymous
3x+y=15 if x=0 then y=15
anonymous
  • anonymous
someone please help me solve this step by step 3x+y=15 4x+5y=9
anonymous
  • anonymous
Refer to the attached plot, \[\text{Plot}\left[\left\{15-3x,\frac{9}{5}-\frac{4 x}{5}\right\},\{x,-1,8\}\right] \] The plot program requires that the two equations be solved for y. It then computes all of the points displayed. For each value of x between -1 and 8 it then computes the corresponding value for y. This plot program was running under an Apple 64 bit OS and the results are instantaneous. The fact is that a line is relatively simple to plot for a human because two points determine a line. If you know where the line crosses the x axis and where it crosses the y axis, then all you have to do is mark the two points on graph paper and draw a line through them with a ruler. The math lingo for these points is the x intercept and y intercept respectively. The process has been described fairly well by polpak's second posting. The expressions in the plot statement are the result of solving for y. If y is zero, in the first expression, then the corresponding x has to be 5 ie: (5,0) If you refer to the plot you will see the blue line crossing the x axis at (5,0). The blue line appears to cross the y axis at 15 or through the point (0,15). That is easy to confirm because when x is zero, 15 - 3x = 15. For the red line, the y intercept is easy to compute because when x = 0, 9/5 - 4/5 times x = 9/5 = 1.8 The solution to the problem is the point coordinates where they cross each other. In this case by eye ball, x=6 for sure and y is close to -3.
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