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## anonymous 5 years ago how do i solve a a problem like this? plz explain in detail

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1. anonymous

$\sqrt{3x+4} = 1 + \sqrt{3x-11}$

2. anonymous

square both sides first

3. anonymous

3x+4 = 1+3x-11 +2(3x-11)^1/2

4. anonymous

but then how do I get rid of the radical so I can solve for x?

5. anonymous

14=2(3x-11)^1/2 7= (3x-11)^1/2 squaring again we get

6. anonymous

49=3x-11 3x=60 x=20

7. anonymous

oh I see...thanks!

8. anonymous

good one !!

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