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anonymous
 5 years ago
someone please help me solve this step by step
3x+y=15
4x+5y=9
anonymous
 5 years ago
someone please help me solve this step by step 3x+y=15 4x+5y=9

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0By graphing? or algebraically?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0by graphing i tried x=0 solve for y but its not right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to graph each line separately

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first equation i came up with (4,3) and did the x=0 solve y for the second

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the first equation: \[x =0 \implies 3(0) + y = 15 \implies y = 15\] \[y =0 \implies 3x + 0 = 15 \implies 3x = 15 \implies x = 5\] This gives the pionts (0,15) and (5,0) So now you can graph the line that corrisponds to the equation 3x+y=15 by drawing the line between those two points.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now do the same for the second equation. and see where the two lines cross.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what do you get for y when you plug in 0 for x in the second equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just leave it as a fraction for now. It's easier to see =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09/5 is correct though. Now plug in 0 for y and solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not quite. As I said, leave it as a fraction. \[y =0 \implies 4x + 5(0) = 9 \implies 4x = 9 \implies x = 9/4 = 2.25\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so what are the two points you have found on this line?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk im confused, i hate this stuff

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0except you keep rounding 2.25 to 2.3 for some reason.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thought i was suppose to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you draw a line between those two points it'll give you the line that corresponds to the second equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think 2 and 1/4 is easier to graph than 2 and 3/10'ths but it depends on your graph paper I suppose.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now you're wanting to find where these two lines intersect.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0according to my graph they dont

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0They must. They don't have the same slope, so they are not parallel. Any two distinct nonparallel lines must intersect somewhere.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You will need to continue the line beyond the points that you graphed. It will go straight through those 2 points, but continue on infinitely.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0equation 1 i got (0,15) (5,0) drew the line 2nd i got (0,1.8) (2.25,0)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Look real close around the point (6,3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i only drew the lines to the points not thru to the end of the graph

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You must extend the lines to the point where they intersect. That point is the solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so then it is considered consistent and dependent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cant figure out how to use my new graphing calc

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The each equation by itself has many solutions all points on the line are solutions. But when you consider the two equations together, the point they intersect is the only point that is a solution to both equations. I am not familiar with term consistent, maybe you can tell me what that term means??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Consistent means that the equations are either the same line (overlapping) or nonparallel. If they are parallel and do not overlap, they are not consistent because there will be no solution. If they are the same line (each one overlaps the other) then they are dependent.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This system is consistent (they aren't parallel) and independent ( they aren't the same line)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Ah so, so you are right tina=ann

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats it, and you can just call me tina

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I believe tina uses her calculator and that is why she comes up with decimal answers rather than the exact fraction

radar
 5 years ago
Best ResponseYou've already chosen the best response.0tina, I have a graphing calculator, bought it new, still in blister pack at a garage sale for $10.00. I haven't learnt how to use it! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i use calc, cant figure out how to use my new graphing calc, just spent 150 cant figure out how to use it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your profile says you graduated from Strayer, that is where i am going

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I guess you use the book and try and follow their examples, eventually you will learn it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok new problem solve by substitution 6x2y=56 5x+48=y

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I went to the Manassas,VA campus, graduated at the Kennedy Center in DC..Ok lets look at the substitution problem. I think we should write the last equation like; y=5x+48 do you agree?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think so i got (40,192) for the solution

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Humor me as I wade through this, you are ahead of me! lol I want to subsitute for y in the first equation so it will look like this: 6x 2(5x+48)=56 6x10x96=56 4x=40 x=10 Did I do that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you did i must of had a brain fart because i forgot to divide

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think I violated any laws of algebra! Now going back to the second equation where we had y=5x+48 substitute are newly found value of x in that we get: y=5(10)+48=2 y=2 The solution according to the above : x=10, y=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then you add 60+48 to get 108 right?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0It is a 50 added to 48. Please go over what I did and question me on any thing I did.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im just relearning this and i wasnt ever good at it to begin with

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You question the solution of 10 for x?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I will put it here so you can ask away. I want to subsitute for y in the first equation so it will look like this: 6x 2(5x+48)=56 6x10x96=56 4x=40 x=10

radar
 5 years ago
Best ResponseYou've already chosen the best response.0It didn't paste so well lol should be a new line after the 56 Note that the (5x+48) was substituted for y inthe first equation. Do you see that?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0However, in the first equation the coefficient of y was a 2 So you have to multiply (5x+48) by 2 It then becomes 10x96

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i got it i new a new one for you two angles are supplementary one angle is 3 degrees less than twice the other. find the measures of the angles

radar
 5 years ago
Best ResponseYou've already chosen the best response.0So now the first equation with the substitution of y looks like this: 6x10x96=56 Combining similar terms it becomes: 4x96=56 and so on.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Two angles are supplementary if their sum is what? Is it 90 or 180 degrees?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0180 complementary is 90

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Let x = one of the angles this then means that 180x is the other angle. Does seem sensible?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was taught x+y=180 x=2y3 (2y3)+y=180 3y3=180 3y=180 y=61 x=2(61)3 x=119 is this right?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I am looking at your work

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You did good until you got to 3y3=180 good so far. Now look at that step after that and find your error

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Did you find your error in that next step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i added 3 instead of subtracting?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Well you should of added 3 to both sides and then you would of had 3y=183

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did and 3y=183 3(61)=183

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I just saw where you had 3y=180 some how you got the right answer lol

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The other angle is supplementary so subtract the 61 from 180 and it is solved!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i wrote it down right on my paper i got lots of math problems. i just need someone to help me solve them or keep it on track so i get the right answers

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Did you say that you have graduated from Strayer or that you are presently going.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I graduated around 1992. I no longer live in VA or work in DC, I am retired and live in the Ozarks of MO. Way out in the woods! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you, im not good at this kind of math
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