This is the last one for now. I hope you guys are on when I take my quiz because there are two problems like this on that I can't get. 1/9x^2+11/3x=432

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This is the last one for now. I hope you guys are on when I take my quiz because there are two problems like this on that I can't get. 1/9x^2+11/3x=432

Mathematics
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This is just like the last problem except where there was 80 you put 432
multiply every term by x^2 and then solve using the quadratic formula.
i think the x^2 is suppose to be in the numerator

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Other answers:

adfriedm I believe the x^2 is on top... just guessing.
fair enough
I don't get the quadratic formula. To me it doesn't make sense
Blasphemy
you can find that formula if you complete the square for ax^2+bx+c=0 so it makes perfect sense
is it (1/9)x^2+(11/3)x=432 or 1/(9x^2)+11/(3x)=432?
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of course it requires a to be non-zero
rihgt! because the quadratic formula is undefined for a=0
well moreover because the proof doesn't follow with a=0
You're just arguing semantics...
not in the slightest
I think what confuses me and I know this is stupid. What is the + sign with the line under it?
it means you have 2 annswers one with + and one with minus
Ok but how do I work this if I have a + and - answer. I'm sorry I just don't get it
\[{-b+\sqrt{b^2-4ac}}/(2a) and ( -b-\sqrt{b^2-4ac})/(2a)\]
it is the a quadratic equation, so we always expect 2 values which make it zero.
OH ok. You guys are a life saver!!! thank you
\[\frac{1}{9 x^2}+\frac{11}{3 x}=432 \] Put the 432 on the left hand side of the equation and combine terms into one fraction. \[\frac{1+33 x-3888 x^2}{9 x^2}=0 \] If the fraction is zero, the Numerator is zero. Factor the Numerator and set the result to zero. x = 1/48 and x = -1/81
Thank you

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