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This is just like the last problem except where there was 80 you put 432

multiply every term by x^2 and then solve using the quadratic formula.

i think the x^2 is suppose to be in the numerator

adfriedm I believe the x^2 is on top... just guessing.

fair enough

I don't get the quadratic formula. To me it doesn't make sense

Blasphemy

you can find that formula if you complete the square for ax^2+bx+c=0 so it makes perfect sense

is it (1/9)x^2+(11/3)x=432
or 1/(9x^2)+11/(3x)=432?

of course it requires a to be non-zero

rihgt! because the quadratic formula is undefined for a=0

well moreover because the proof doesn't follow with a=0

You're just arguing semantics...

not in the slightest

I think what confuses me and I know this is stupid. What is the + sign with the line under it?

it means you have 2 annswers one with + and one with minus

Ok but how do I work this if I have a + and - answer. I'm sorry I just don't get it

\[{-b+\sqrt{b^2-4ac}}/(2a) and ( -b-\sqrt{b^2-4ac})/(2a)\]

it is the a quadratic equation, so we always expect 2 values which make it zero.

OH ok. You guys are a life saver!!! thank you

Thank you