## anonymous 5 years ago This is the last one for now. I hope you guys are on when I take my quiz because there are two problems like this on that I can't get. 1/9x^2+11/3x=432

1. anonymous

This is just like the last problem except where there was 80 you put 432

2. anonymous

multiply every term by x^2 and then solve using the quadratic formula.

3. myininaya

i think the x^2 is suppose to be in the numerator

4. anonymous

adfriedm I believe the x^2 is on top... just guessing.

5. anonymous

fair enough

6. anonymous

I don't get the quadratic formula. To me it doesn't make sense

7. anonymous

Blasphemy

8. myininaya

you can find that formula if you complete the square for ax^2+bx+c=0 so it makes perfect sense

9. anonymous

is it (1/9)x^2+(11/3)x=432 or 1/(9x^2)+11/(3x)=432?

10. myininaya

11. anonymous

of course it requires a to be non-zero

12. myininaya

rihgt! because the quadratic formula is undefined for a=0

13. anonymous

well moreover because the proof doesn't follow with a=0

14. anonymous

You're just arguing semantics...

15. anonymous

not in the slightest

16. anonymous

I think what confuses me and I know this is stupid. What is the + sign with the line under it?

17. myininaya

it means you have 2 annswers one with + and one with minus

18. anonymous

Ok but how do I work this if I have a + and - answer. I'm sorry I just don't get it

19. myininaya

${-b+\sqrt{b^2-4ac}}/(2a) and ( -b-\sqrt{b^2-4ac})/(2a)$

20. anonymous

it is the a quadratic equation, so we always expect 2 values which make it zero.

21. anonymous

OH ok. You guys are a life saver!!! thank you

22. anonymous

$\frac{1}{9 x^2}+\frac{11}{3 x}=432$ Put the 432 on the left hand side of the equation and combine terms into one fraction. $\frac{1+33 x-3888 x^2}{9 x^2}=0$ If the fraction is zero, the Numerator is zero. Factor the Numerator and set the result to zero. x = 1/48 and x = -1/81

23. anonymous

Thank you