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anonymous
 5 years ago
Double integral x^2 dA; bounded by region y=16/x, y=x, x=8. My answer coming wrong. Need help with setup.
anonymous
 5 years ago
Double integral x^2 dA; bounded by region y=16/x, y=x, x=8. My answer coming wrong. Need help with setup.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi chaguanas, I have an answer for you. I'm pretty tired, so will just attach what I did. If you need further clarification, let me know. I broke the region into two parts and computed the integral as per my (scratchy) working on the other attached document.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm dead tired, so check everything, please :) Let me know if you need me to clarify anything (I was going to type it out with explanations, but...dead tired :( ).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks you're the best. My book is coming up with 576 so I wonder, choice of region. I know you're tired. This is something I can do myself. You have shown me how to break it up in regions. I would get back to you
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