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You just have to distribute the multiplication to each term
\[(a + b)(c) = ac + bc\]

Okay....

why adding?

Why not?

isnt it multiplying? (-2*-9)

So in your case you have (-2x -9)(-4) which is the same as
(-2x + (-9))(-4)

Oh, is that x for multiplication? or is it an x.

i think its multiplying... idk

i think it is just an x

ohh ok

So did that make sense with what you need to do Artist, or do you need a bit more help?

I'm not sure....

So in your case, what is the sum you're multiplying ?

(-2 x - 9)(-4)

Not quite.
(-2x - 9) is a sum.

Specifically it is the sum of -2x and -9

Okay

You know what a sum is right?

Yes...

Tell me =)

Okay.

What is a sum?

A sum is the answer of two numbers added together...

Oh...Okay.

Now then. For each of the sums I listed above, count the number of terms in each sum.

2, then 4?

So how many terms does that last sum have?

*Lightbulb*...Okay...

3?

I am glad I fanned you btw. You've been the best student I've seen here in a long time.

Yes, it has 3.

Really?

Yes.

I'm the best?

So far ;)

Cool...

okay...

So lets look at your problem again.

(-2x - 9)(-4)
What is the sum, and what is k?

the sum is (-2x-9)?

Can you rewrite subtraction as adding a negative?

no...?

2-9 = 2+(-9)
-7 = -7
Right?

Yes.

So do the same thing to the subtraction you have in your sum

I like my sums to only have addition.

feels neater ;p

Yeah...

so, -2x + (- 9,) ?

Yes.

So what do you get?

-4*-2+ -4*-9?

Close. Don't forget your x.

8x + 36

like that?

Yes, exactly.

:)

Nice work!

Thank you!