a plane traveled 285 miles to Perth and back. The trip there was with the wind. It took 3 hours. The trip back was into the wind. The trip back took 5 hours. What is the speed of the plane in still air? What is the speed of the wind?
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x = speed of the plane
y = speed of the wind
one way trip is 285/2 = 142.5 miles
d = rt
d = (x + y)3 (the wind helps you out so you add x and y)
d = (x - y)5 (the wind hurts you so you subtract x and y)
142.5 = 3x + 3y
142.5 = 5x - 5y
Multiply top by -5 and bottom by 3 so the y's cancel
-5(142.5 = 3x + 3y)
3(142.5 = 5x - 5y)
do you know how to solve from here?