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anonymous
 5 years ago
Implicit differentiation, equation to follow
anonymous
 5 years ago
Implicit differentiation, equation to follow

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x}+\sqrt{y}=5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would this just be \[x^1/2+y^1/2=\]

heisenberg
 5 years ago
Best ResponseYou've already chosen the best response.0what are you attempting to derive?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am trying to find dy/dx of the above equation

heisenberg
 5 years ago
Best ResponseYou've already chosen the best response.0it's been a while so i may be fuzzy, but the basic gist is: 1. Since we are doing dy/dx, treat all 'x's as constant and take the derivative. 2. When you derive a 'y' term, also include a dy/dx 3. solve for dy/dx

heisenberg
 5 years ago
Best ResponseYou've already chosen the best response.0so i THINK: \[x^\frac{1}{2} + \frac{1}{2}*y^\frac{1}{2}*\frac{dy}{dx} = 0\]

heisenberg
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dy}{dx} =  2 * \sqrt y * \sqrt x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Think you are mixing up you partial differentiation with your single variable calculus

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In single variable cal, you differentiate the x also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would the fourmula be\[x+dy/dx+y+dy/dx\]

heisenberg
 5 years ago
Best ResponseYou've already chosen the best response.0i don't know that you have to use implicit differentiation to solve this actually. can't you just solve for y and then derive?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0start from the top. Differentiate each item; the y item you write in dy/dx next to it. Solve for dy/dx. There is no formula per se zbay. You differentiate and then solve for dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks let me attempt to work it out
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