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anonymous

  • 5 years ago

find a quadratic formula that has x-intercepts of (2,0) and (-6,0) and has a maximum point of (-2,4)

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  1. anonymous
    • 5 years ago
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    Okay. write down the standard form of a quadratic equation and post it here.

  2. anonymous
    • 5 years ago
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    ax^2+bx=c

  3. anonymous
    • 5 years ago
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    ax^2+bx+c

  4. anonymous
    • 5 years ago
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    No, it should be y = ax^2+bx +c

  5. anonymous
    • 5 years ago
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    alright, now substitute (2,0) and (-6,0) in the equation.

  6. anonymous
    • 5 years ago
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    maximum point is arrived at when you take the derivative of y with respect to x and equate it to zero.

  7. anonymous
    • 5 years ago
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    whats derivative mean

  8. anonymous
    • 5 years ago
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    dy/dx

  9. anonymous
    • 5 years ago
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    you shouldn't be doing this problem without learning calculus.

  10. anonymous
    • 5 years ago
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    my teacher is an idiot and she doesnt teach us

  11. anonymous
    • 5 years ago
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    Oh okay. Well, I can only point you to this: http://www.youtube.com/watch?v=CtRAHmeWSC0

  12. anonymous
    • 5 years ago
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    you can also check out khanacademy on youtube. he gives good intro videos on many levels of math

  13. anonymous
    • 5 years ago
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    yes. that is right.

  14. anonymous
    • 5 years ago
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    You don't need the derivative for this. Just plug in your 3 points into x and y to find 3 linear equations with 3 variables (a, b, and c). Then solve this system of equations to get the coefficients of your quadratic.

  15. anonymous
    • 5 years ago
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    It's a system problem, not a calculus one.

  16. anonymous
    • 5 years ago
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    lol, yes. polpak is right. sorry.

  17. anonymous
    • 5 years ago
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    np. We all have our moments.. For example, I had to be reminded how to integrate odd powers of tan x a few mins ago.

  18. anonymous
    • 5 years ago
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    heh. that is true. We all have our moments. :)

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