anonymous
  • anonymous
find a quadratic formula that has x-intercepts of (2,0) and (-6,0) and has a maximum point of (-2,4)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Okay. write down the standard form of a quadratic equation and post it here.
anonymous
  • anonymous
ax^2+bx=c
anonymous
  • anonymous
ax^2+bx+c

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anonymous
  • anonymous
No, it should be y = ax^2+bx +c
anonymous
  • anonymous
alright, now substitute (2,0) and (-6,0) in the equation.
anonymous
  • anonymous
maximum point is arrived at when you take the derivative of y with respect to x and equate it to zero.
anonymous
  • anonymous
whats derivative mean
anonymous
  • anonymous
dy/dx
anonymous
  • anonymous
you shouldn't be doing this problem without learning calculus.
anonymous
  • anonymous
my teacher is an idiot and she doesnt teach us
anonymous
  • anonymous
Oh okay. Well, I can only point you to this: http://www.youtube.com/watch?v=CtRAHmeWSC0
anonymous
  • anonymous
you can also check out khanacademy on youtube. he gives good intro videos on many levels of math
anonymous
  • anonymous
yes. that is right.
anonymous
  • anonymous
You don't need the derivative for this. Just plug in your 3 points into x and y to find 3 linear equations with 3 variables (a, b, and c). Then solve this system of equations to get the coefficients of your quadratic.
anonymous
  • anonymous
It's a system problem, not a calculus one.
anonymous
  • anonymous
lol, yes. polpak is right. sorry.
anonymous
  • anonymous
np. We all have our moments.. For example, I had to be reminded how to integrate odd powers of tan x a few mins ago.
anonymous
  • anonymous
heh. that is true. We all have our moments. :)

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