anonymous
  • anonymous
A ball is dropped from a height of 3 ft. The elasticity of the ball is such that it always bounces up one-third the distance it has fallen. (a) Find the total distance the ball has traveled at the instant it hits the ground the fourth time. (Enter your answer as an improper fraction.)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
is the answer 40/9?
anonymous
  • anonymous
no that doesnt work
anonymous
  • anonymous
This how I solved it: Suppose K=1/3 first time d1=3 second time d2=3*K=1 Third time d3=1*k=1/3 Forth time d4=K(1/3)=1/9 Now adding up d1+d2+d3+d4, we get the total distance d=40/9

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anonymous
  • anonymous
Sorry I made a huge mistake. Im gonna correct it
anonymous
  • anonymous
That looks right to me but my online homework says its wrong...
anonymous
  • anonymous
ok
anonymous
  • anonymous
Suppose K=1/3 first time d1=3 second time d2=2*(3*K)=2 Third time d3=2*(2*k)=4/3 Forth time d4=2*K(4/3)=8/9 Now adding up d1+d2+d3+d4, we get the total distance d=65/9. Is that correct. Hopefully yes
anonymous
  • anonymous
it still says its wrong...?
anonymous
  • anonymous
What is the correct answer?
anonymous
  • anonymous
IDK. in my book it gives a similar problem who's answer is 17 8/9
anonymous
  • anonymous
its the same problem only the ball is dropped from 9 feet instead of 3 ft
anonymous
  • anonymous
What you mean by 17 8/9?
anonymous
  • anonymous
the answer is a mixed number
anonymous
  • anonymous
Convert this number in a decimal number. Cannot remember how to do that!
anonymous
  • anonymous
ok
anonymous
  • anonymous
Is 17(8/9) the answer for the problem you have to solve? It doesnt make any sense!
anonymous
  • anonymous
no that was the answer to a similar problem. I thought if i gave you that answer then it might help you figure out the the problem
anonymous
  • anonymous
Yeah coz im trying to help you. Or are you challenging me?
anonymous
  • anonymous
A ball is dropped from a height of 9 ft. The elasticity of the ball is such that it always bounces up one-third the distance it has fallen. (a) Find the total distance the ball has traveled at the instant it hits the ground the fourth time. the answer to this is 17 (8/9)
anonymous
  • anonymous
But I need the answer for the problem your are solving now dude.
anonymous
  • anonymous
I dont know the answer to that one thats why im on here!
anonymous
  • anonymous
I got 53/9
anonymous
  • anonymous
Convert 65/9 in a mixed number
anonymous
  • anonymous
53/9 works!
anonymous
  • anonymous
Convert 211/27 ins a mixed number too
anonymous
  • anonymous
What formula did you use?
anonymous
  • anonymous
Can you write down step by step, how you got 53/9?
anonymous
  • anonymous
You start at 3 fall 3 rise (3 * 1.3) =1 fall 1 rise ( 1 * 1/3) = 1/3 fall 1/3 rise (1/3 * 1/3) = 1/9 fall 1/9 I stop at 1/9 because at fall 1/9 is the 4ht instant I hit the ground. add 3 + 1 + 1 + 1/3 + 1/3 + 1/9 + 1/9 5+ 2/3 + 2/9 5 + 6/9 + 2/9 5 + 8/9 45/9 + 8/9 53/9
anonymous
  • anonymous
The formula of the the that is droped from 9 ft is 18-(1/3)^n-3. so i assume that the ball droped from 3ft had a similar formula...
anonymous
  • anonymous
the= ball
anonymous
  • anonymous
I can derive a formula but it will be hard since you start from the top and you want to know the distance it travels on the fourth hit to the floor.
anonymous
  • anonymous
ok thats cool. you got the answer right. Thanks!
anonymous
  • anonymous
btw the formula you use gives you 53/3 not 53/9 for the 4th hit.
anonymous
  • anonymous
Are you talking about the problem were the ball is droped from 9ft?
anonymous
  • anonymous
THe way I visualized it was right. However I made a mistake in fraction reduction. Sorry to dissapoint
anonymous
  • anonymous
Hey its cool man. I appreciate the help!
anonymous
  • anonymous
OK thanks. I like to help

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