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work = force times distance
let me see if I recall the formula..
distance moved is from 4-y for any given section; weight for any given volume is 50 times pir^2
since it is half full we integrate from 0 to 2
[S] 50pi r^2 (4-y) dy sound about right?
The answer was right, but one question.
Is the volume of the cylindrical oil considered as 50(pi)r^2 dx ?
r in this case is a constant i beleive since the shape has straight sides
if it was conic; then radius would change with respect to x or y depending on its orientation
sin ce we are lifting in the vertical direction; the sums are added vertically up the y..or down the y :)
Let me try it again and see if I can do it on my own.
ok :) I think you can ;)
Great, it was a simple mistake I had there. I get it now. I really appreciate your help. I have to take a AP calculus diagnostic exam next week for a job interview and it will decide if I can marry my girl or not.