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Did you try to figure out how to solve it?

took* time t

nikki, we need you to give us some feedback in order to help you.

yeah, solving your math homework is not the point of Openstudy

I did try...I ended up with 2 different variables and cannot solve.

Write down what you got. We can correct you

I got for the return trip 180=2r(t-3)

r is the speed and t is time

right, what is the going trip formula?

180=r(t+3)

I do not know the time to figure out the speed

If im not mistaken the original should be 180 = r* (t)

ok but how do you figure out the time to get the rate?

why did you write 180 = r(t+3)? Does the trucker take 6 extra hours on the way to the destination?

well simplify the second equation

first define what t is.

because I added three hours to the time of the return trip

t is time

define what t is. what do you mean by t?

t is time taken to do what?

the time for the total distance of 180

time for total distance of 180? what does that mean? how can time be for distance?

Nikki, t represents the time of the going trip

What it the time of the going back trip?

I think this is a classic mechanic problem. So you can use the velocity formula (V=d/t)

right, so it takes t amount of time, going at speed r to reach 180 miles.

so 180 = t*r

yes i have that. but how do you find the speed from that with another variable

yes!!! thank you i got it from here!!! much thanks

so substitute t = 180/r in equation 2 and post what you got.

alright, you are welcome.

30=r