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anonymous

  • 5 years ago

2^(5/2)-2^(3/2)

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  1. anonymous
    • 5 years ago
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    Do you have any idea how to solve it?

  2. anonymous
    • 5 years ago
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    I dont

  3. anonymous
    • 5 years ago
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    Im completely lost.

  4. anonymous
    • 5 years ago
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    You can do the following: 2* Sqrt[2]+2S*qrt(2)

  5. anonymous
    • 5 years ago
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    i might have an idea ...

  6. anonymous
    • 5 years ago
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    sorry: =4*sqrt(2)+2*sqrt(2) =6*sqrt(2)

  7. anonymous
    • 5 years ago
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    That is the answer

  8. anonymous
    • 5 years ago
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    \[\sqrt{2^{5^{}}}-\sqrt{2^{3}}= 2^{5/2}-2^{3/2}\]

  9. anonymous
    • 5 years ago
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    right?

  10. anonymous
    • 5 years ago
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    ...and that = \[2\sqrt{2^{3}}-\sqrt{2^{3}}\]

  11. anonymous
    • 5 years ago
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    ....

  12. anonymous
    • 5 years ago
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    The answer is 2^(3/2)

  13. anonymous
    • 5 years ago
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    ... and continue

  14. anonymous
    • 5 years ago
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    continue what?

  15. anonymous
    • 5 years ago
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    that equals \[\sqrt{2^{3}}\]

  16. anonymous
    • 5 years ago
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    which equals ...

  17. anonymous
    • 5 years ago
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    =4*sqrt(2)+2*sqrt(2) =6*sqrt(2) if sqrt(2)=2^(1/2), we have that: 6*sqrt(2)=6^(1/1)*(2^(1/2)) =(6*2)^(1+1/2) =12^3/2

  18. anonymous
    • 5 years ago
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    THat is what i got

  19. anonymous
    • 5 years ago
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    how the hell did u get that from the equation we stared with....just asking lol

  20. anonymous
    • 5 years ago
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    \[\sqrt{2^{3}}=2\sqrt{2}\] or \[\sqrt{8}=2\sqrt{2}\] right?

  21. anonymous
    • 5 years ago
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    sqrt(any_number)<=>(any_number)^(1/2)

  22. anonymous
    • 5 years ago
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    yes

  23. anonymous
    • 5 years ago
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    \[x ^{1/2}=\sqrt{x}\]

  24. anonymous
    • 5 years ago
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    sqrt(8)=sqrt(2*4) if 4=2^2 then you can get sqrt(4)=2 so sqrt(8)=2*sqrt(2) You are right Terra B Can you teache me how to write down the sqrt symbol please

  25. anonymous
    • 5 years ago
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    press the equation button below the place you type here. it's to the bottom left

  26. anonymous
    • 5 years ago
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    then a box with symbols pops up

  27. anonymous
    • 5 years ago
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    \[\sqrt{x}+3\]

  28. anonymous
    • 5 years ago
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    yeah

  29. anonymous
    • 5 years ago
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    I got it! Thanks guys. Now it is gonna be more fun besides openstudy. Thanks Im gonna become your fan

  30. anonymous
    • 5 years ago
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    sweet i hope your work goes well

  31. anonymous
    • 5 years ago
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    Thanks, but Im a student yet

  32. anonymous
    • 5 years ago
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    hey he just wants to get ur pants peace out guys;)

  33. anonymous
    • 5 years ago
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    :)

  34. anonymous
    • 5 years ago
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    Ok time to move on. See you guys,

  35. anonymous
    • 5 years ago
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    :]

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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