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anonymous
 5 years ago
lim sigma>0 g(x), where g(x) = (e^(x^2/sigma^2))/(sigma*sqrt(Pi))
anonymous
 5 years ago
lim sigma>0 g(x), where g(x) = (e^(x^2/sigma^2))/(sigma*sqrt(Pi))

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0can you rewrite that; its hard to parse

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use m for sigma, might clean it up alot

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lim{m>0} g(x) g(x) = e^(x/m)^2  m sqrt(pi)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0exponents multipy right? 2x/m right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lim{m>0} g(x), where g(x) = (e^(x/m)^2)/(m*sqrt(Pi))...sorry it appeared so confusing originally. It is the limit of a Gaussian.
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