Consider the area between the graphs x+3y=1 and x+9=y2. This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals; Alternatively this area can be computed as a single integral

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Consider the area between the graphs x+3y=1 and x+9=y2. This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals; Alternatively this area can be computed as a single integral

Mathematics
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and the question for this statement?
we can integrate them both at the same time, or seperately and add the sums...
I need both please!

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And I need a and b, as well as c
the common line between them is the sum of there parts./2 right? gets an averge?
I also need f(x) and g(x) separately
f(x)=-x/3 +1/3; g(x) = sqrt(x+9)
[S] f(x) dx - [S] g(x) dx [S] f(x) - g(x) dx
The fist thing you have to do is to find the intersection of the two lines. Secondly, you have to find the intersection of the two lines with the x axis. As the third step, you have to integrate the frist integral from the x-coordinate of the first line until the x-cordinate of the intersection point. You have to do the same with the seconde line
it doesnt provide an interval, and so assuming that it just wants the intersections is presumptuous; prolly true, but not accurate
it could want the interval [0,root to the right]
Im not sure how to do that. Sorry
you get something that looks like this
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without a stated interval, you are prolly correct in assuming the left and right intercepts
ahhh ok. give me one second to thing about it
its got issues of being on the other side of the y axis; and youd have to split it into intervals from the common point to the left and right
maybe +9 to get it all on the right side of the y axis?
and my line parts to steep , but its just an artist interpretation lol
kinda like this eh
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Anyway, you have to split the total area in two sides.Carry out integration from intersection of the parable and the x-axis until the intersection of the parable and the line. They you have to integrate from the intersection point to the intersection of the line with the x-axis. That is how I would do that my friend
I got x=1 for c, but it keeps saying that it's wrong.
which c?
the end point on the right
I dont know my friend. I got a little bit confused. Sorry :(

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