Suppose that at the end of any given year an automobile is only worth 80% of it's value a the beginning of that year. If a car cost 21,000 new, what is it's value at the end of five years?

- anonymous

- chestercat

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- dumbcow

21000*(1-0.8)^5

- dumbcow

ignore that post sorry

- anonymous

lol.

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## More answers

- dumbcow

21000*(0.8^5)
:)

- radar

1st yr .8x$21000=$16800
2nd yr .8 x 16800=13440
3rd yr .8 x 13440=10752
4th yr .8 x 10752=8601.60
5th yr .8 x 8601.60=$6881.28

- anonymous

hmmmmm...........

- radar

Or as dumbcow stated\[21000*.8^{5}\]

- anonymous

BAM! both of you two were right! I just had to round down. Thanks so much on this one guys!

- anonymous

A company offers a starting yearly salary of 31,000, with raises of 2,000 per year. Find the total salary over a ten-year period.

- anonymous

Something tricky about this one, it's like 300k, or 400k sumthin...

- dumbcow

First find salary at end of ten-year period
A10 = 31000+(10-1)*2000
A10 = 49000
Then use series sum formula
Sum = 1/2*n*(A1+A10)
Sum = 1/2*10*(31000+49000)
...

- anonymous

.......

- dumbcow

thats left for you to compute ;)

- anonymous

I am a bottom line kind of girl..... :)

- anonymous

It doesn't add up.......hmmm...

- anonymous

Sigh....

- dumbcow

what did you come up with?

- anonymous

Hello.

- anonymous

Ah well.......I came up with a bunch of letters I don't understand.

- dumbcow

what do you mean?
Sum = 1/2*10*(31000+49000)
sum= 5*(80,000) = 400,000

- anonymous

....

- anonymous

SO it's 400k + 80k?

- dumbcow

where did the 80k come from?

- anonymous

31+49

- anonymous

So it's 400K even?

- anonymous

BINGO!

- dumbcow

yes
sorry for the confusion

- anonymous

Can you help the other Kelley? Same question, different numbers. Like 6 people are trying it now, and can't help her get this question!

- dumbcow

um yeah

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