A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

Find the volume of the solid formed by rotating the region enclosed by x=0 x=1 y=0 y=9+x3

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What is the axis of rotation? I'll assume we're letting y = 0 be the axis of rotation. The volume of a solid is given by: \[V = \int\limits_{a}^{b}A(x)dx\] where A(x) is the area of a cross section made perpendicular to the x-axis. Since we are rotating, the cross section is a circle. Its radius is given by f(x) = 9 + x^3 - 0 = 9 + x^3. \[A = \pi (9 + x^3)^2\] We are finding the volume from x = 0 to x = 1, so \[V = \pi \int\limits_{0}^{1}(9+x^3)^2dx\] Using the fundamental theorem of calculus, you should find that the volume is (1199/14)*pi

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.