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anonymous
 5 years ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
x=6y^2, y=1, x=0 about the yaxis
anonymous
 5 years ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. x=6y^2, y=1, x=0 about the yaxis

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well first, you need to have an idea what this giddyup look like. In x=6y^2 you can solve for y and punch in it your calculator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've been trying for a while now, and I can't figure it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 3. I'm not sure how to set it up.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well you should still have an x. x=6y^2 x/6=y^2 (sq rt x)/(sq rt 6)=y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I shouldn't get an x in the final answer... My final answer was 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1}Pix ^{2}dy\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You are just manipulating the equation, so that it fits into your calculator at the y= button. You don't get rid of x unless you are solving for a specific something and then you would have a value of x to enter. This is just the preliminary stage to find out what the graph looks like.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can't even get to that point. I'm so lost.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't worry about it. I already gave you. Put in your calculator graphing function y=(square root of x)/(square root of 6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay I got the graph.... What do I do with that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Draw that line on a piece of paper and then draw the line y=1. The graph they are describing is the space between the thing from your calculator, x=0, y=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got that far before and got the answer 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I don't know what the answer is. I was just trying to get to visualize what the problem is saying, which is the first step in solving these kind of problems.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can visualize it; I just don't know how to set it up. Thank you though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am showing you how to do it and any problem like it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Think of it as making disks. The volume of a cylinder is pi*r^2*h. If you have your graph as f(y) and are rotating around the y axis, then imagine: cylinder with height dy and radius f(y). So you sum up these cylinders by integrating from y=0 to y=1 using the formula for the volume of a cylinder. That's how im visualizing it. So i'm getting what duct said
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