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I've been trying for a while now, and I can't figure it out

What did you get?

I got 3. I'm not sure how to set it up.

Well you should still have an x.
x=6y^2
x/6=y^2
(sq rt x)/(sq rt 6)=y

I shouldn't get an x in the final answer... My final answer was 3.

\[\int\limits_{0}^{1}Pix ^{2}dy\]

I can't even get to that point. I'm so lost.

Okay I got the graph.... What do I do with that?

I got that far before and got the answer 3.

I can visualize it; I just don't know how to set it up. Thank you though.

I am showing you how to do it and any problem like it.