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anonymous
 5 years ago
Evaluate the integral from infinity to infinity of [(t^2+5t)*dirac(t2)dt]
anonymous
 5 years ago
Evaluate the integral from infinity to infinity of [(t^2+5t)*dirac(t2)dt]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wiki says that the intergral from infinity to infinity of f(t)dirac(tT)dt is equal to f(T). So i guess if you distribute and split up the integral it becomes (2)^2+5(2)=14

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What type of couse is this for? Just curious

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Darn, I was going about it all wrong lol.. And it's for a linear algebra/differential equations class

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In my textbook it's talking about how dirac(t) = lim h > 0 [g(h(t)] and then you plug it into the general equation, but I don't really get the whole limit part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, it's supposed to be g sub h of t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What function is g sub h?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh whoops, I forgot to add that part, it's a heavyside function. g sub h = (1/h)[H(t)H(th)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The limit part. I guess the dirac function is the derivative of the heavyside

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If "dirac" is the DiracDelta function then, \[\int\limits _{\infty }^{\infty }\left(5 t+t^2\right) \delta (2+t)dt=14 \] Browse over to WolframAlpha.com and paste in the following: Integrate[(t^2 + 5 t) DiracDelta[2 + t], {t, Infinity, Infinity}]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry about the double posting. Using Firefox and it seems to have a hair trigger.
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