After sailing 15 miles, a sailor changed direction and increased the boat's speed by 2mph. An additional 19 miles was sailed at the increased speed. The total sailing time was 4 hours. FIND THE RATE OF THE BOAT FOR THE FIRST 15 MILES.
Is this formula correct that I set up?
I know that the time being the same I can set them equal to one another
Stacey Warren - Expert brainly.com
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sorry didn't mean to repeat the question
I have my formula corrected in this second one
ok so you have the correct equation you just need to solve for r
combine fractions on left side
add like terms
i think you will get a quadtratic so use quadratic formula
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Ok I got 15(2r)=19r+4r^2=8r^2?? Is that right?
hmm not quite
it should be r+2 not 2r
15/r + 19/r+2 = 4
sorry I thought because he increased by 2 miles per hour that it was going to be times
how can I tell the difference?
if i said i doubled my speed then i went from 10mph to 20mph
i multiplied by 2
if i said i increased my speed by 4mph, then i went from 10mph to 14 mph
i added 4
after you combine fractions you should get
15(x+2) + 19x = 4x(x+2)
oh i used x instead of r
Yes, thank you for making sure I got the quadractic right. I stumble sometimes when I am combining
d = rt
15 = xt let x be the first rate
19 = (x + 2)t
solve both for t
-- = t
----- = t
x + 2
We know their combined time was 4 hours.. so we will add these together to get 4
-- + ----- = 4
common denominator of x(x + 2) you multiply every term by that
x(x+2)15 x(x+2)19 x(x+2)4
-------- + -------- =
x x + 2
cancel the bottoms into the tops
(x + 2)15 + x(19) = 4x(x+2)
15x + 30 + 19x = 4x^2 + 8x
34x + 30 = 4x^2 + 8x
0 = 4x^2 - 26x - 30
0 = 2(2x^2 - 13x - 15)
0 = 2(2x - 15)(x + 1)
x = 15/2 or -1 since hours can't be negative we use the 15/2
15/2 = 7.5
x = 7.5 mph
thank you blextiing
I missed my quadractic like I knew I would putting a 32 where there was supposed be a 36
i mean 26