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Find the mean: xbar Subtract the mean from each data point. (x1-xbar),(x2-xbar)...etc Square the difference. (x1-xbar)^2,(x2-xbar)^2..etc Take the average of the square differences [(x1-xbar)^2+(x2-xbar)^2+...+(xn-xbar)]/n Take the square root of that average.
i have to answer dont know if there right though 40 or 8
Well if its sample standard deviation you have to divide by n-1 which is 4. Thats probably how you got 10. But you have to take the square root of that value.
& itss outta 40 & 8 too
40 is not correct. You need to divide by n or n-1 You divide by n if the data set is the population. By n-1 if its a sample. If we just assume its the population you get sqrt(8). Remember to take the square root
i think itss 10
i did it in a standard deviation calculator & it qive me 3.16228 this & to qet thts is 10
"If you simply want to quantify the variation in a particular set of data, and don't plan to extrapolate to make wider conclusions, then you can compute the SD using n in the denominator. The resulting SD is the SD of those particular values. It makes no sense to compute the SD this way if you want to estimate the SD of the population from which those points were drawn. It only makes sense to use n in the denominator when there is no sampling from a population, there is no desire to make general conclusions." http://www.graphpad.com/faq/viewfaq.cfm?faq=1382 So we assume the data set given is the sample. Then sqrt(10) is right
The population i mean =/
why Yu put tha sad face .
Because i would have left that wrong statement there. So we assume this is the population and use n as the denominator. Gives sqrt(8)