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\[\left\{ 2x+y=-7 \right\}\]

how do we graph in a text based area?

the best we can do is set up a table of solutions

\[\left\{ -3x-2y=14 \right\}\]

substitution works pretty well in this scenario:
can you solve the first equation for y?

yes

so, i subtract the 2y

-2x yes

ok

so i get

y = -7-2x; lets use this 'value' in the next equation

y=-2x-7

that ways good too ;)

doesnt the -2x come before because it has an x

ok

-3x -2y = 14 - lets use that y value in this equation and solve for 'x'

and for the other one i subtract the -3x

To solve by graphing just means, draw the two lines and see where (if ever) they intersect.

lets keep the other one as is and use out y value in it

-3x -2y = 14
-3x -2(-2x-7) = 14 can you slove this ?

yes\

let me see you do it ;)

ok

ohh wait i dnt think i can solve this because it has two # before the paratheses

oh ok

-3x +4x = 0
it just takes a little bit to be able to 'see' the problem :)
x = 0
this is our solution

wait how did u get the x to = 0

First step; plug in the value for y
-3 -2(-2x-7)= 14 ; now distribute the -2 thru the paranthesis

-3x +4x +14 = 14 do you see what i did there?

you did distributive property

yes, and since that was (-2) I used it in the process

-3x +4x +14 = 14 ; now we subtract 14 from both sides
-3x +4x +14-14 = 14-14

and got 0

correct; -3x +4x = 0
x = 0

but dnt we have to get the values bythemselfs first

by themselves? what are you refering to?

like -3x-4x=0

subtract then divide

-3x+4x = 0 combine like terms
-3x+4x = 1x right?

yes

then divide

yes, we do divide by 1 if we need to :)
then 1x = 0 ....x = 0

oh ok

in my multiple choices i do not have any one that has x=0

they all start with 4 or -4

and y has 1 or -1

we use 0 to find the value of y now and your choices are going to be (0,y)

but there is no choice for that with 0.

remember we found that y = -2x-7 right?

yes

unless you gave me the wrong equation information, this is what the answer needs to be :)

no its all correct

y = -2(0) - 7
y = -7

its jst that they are on top of eachother .

lets see if these answers work;
-3(0)-2(-7)=14
0+14=14

14=14

2x+y = -7
2(0) + -7 = -7
0 +-7 = -7
-7=-7

correct.

so we have the correct solution; but what are your answer to choose from look like?

(-4,-1) (4,1) (-4,1) (4,-1)

....... then either those go to a different problem; or they are simply wrong :)

i think they are wrong but idk.

there can only be one solution to lines that cross; it is the point we found (0,-7)

the problem is correct

ok well thanks.:)

if you ahve a teacher, bring it to their attention :)

yes i will do that

tag!!

Stop that.

lol tag

Really really annoying.