i need help solving this system by graphing??

- anonymous

i need help solving this system by graphing??

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- anonymous

\[\left\{ 2x+y=-7 \right\}\]

- amistre64

how do we graph in a text based area?

- amistre64

the best we can do is set up a table of solutions

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## More answers

- anonymous

\[\left\{ -3x-2y=14 \right\}\]

- amistre64

substitution works pretty well in this scenario:
can you solve the first equation for y?

- anonymous

yes

- anonymous

so, i subtract the 2y

- amistre64

-2x yes

- anonymous

ok

- anonymous

so i get

- amistre64

y = -7-2x; lets use this 'value' in the next equation

- anonymous

y=-2x-7

- amistre64

that ways good too ;)

- anonymous

doesnt the -2x come before because it has an x

- amistre64

it doesnt need to, but if you like it there; we can keep it there... it gets used up in the next one regardless

- anonymous

ok

- amistre64

-3x -2y = 14 - lets use that y value in this equation and solve for 'x'

- anonymous

and for the other one i subtract the -3x

- anonymous

To solve by graphing just means, draw the two lines and see where (if ever) they intersect.

- amistre64

lets keep the other one as is and use out y value in it

- amistre64

-3x -2y = 14
-3x -2(-2x-7) = 14 can you slove this ?

- anonymous

yes\

- amistre64

let me see you do it ;)

- anonymous

ok

- anonymous

ohh wait i dnt think i can solve this because it has two # before the paratheses

- amistre64

-3x -2(-2x-7) = 14
-3x +4x +14 = 14
-3x +4x +14-14 = 14-14
-3x +4x +0 = 0
the two numbers are seperate terms, they dont interfere with each other

- anonymous

oh ok

- amistre64

-3x +4x = 0
it just takes a little bit to be able to 'see' the problem :)
x = 0
this is our solution

- anonymous

wait how did u get the x to = 0

- amistre64

First step; plug in the value for y
-3 -2(-2x-7)= 14 ; now distribute the -2 thru the paranthesis

- amistre64

-3x +4x +14 = 14 do you see what i did there?

- anonymous

you did distributive property

- amistre64

yes, and since that was (-2) I used it in the process

- amistre64

-3x +4x +14 = 14 ; now we subtract 14 from both sides
-3x +4x +14-14 = 14-14

- anonymous

and got 0

- amistre64

correct; -3x +4x = 0
x = 0

- anonymous

but dnt we have to get the values bythemselfs first

- amistre64

by themselves? what are you refering to?

- anonymous

like -3x-4x=0

- anonymous

subtract then divide

- amistre64

-3x+4x = 0 combine like terms
-3x+4x = 1x right?

- anonymous

yes

- anonymous

then divide

- amistre64

yes, we do divide by 1 if we need to :)
then 1x = 0 ....x = 0

- anonymous

oh ok

- anonymous

in my multiple choices i do not have any one that has x=0

- anonymous

they all start with 4 or -4

- anonymous

and y has 1 or -1

- amistre64

we use 0 to find the value of y now and your choices are going to be (0,y)

- anonymous

but there is no choice for that with 0.

- amistre64

remember we found that y = -2x-7 right?

- anonymous

yes

- amistre64

unless you gave me the wrong equation information, this is what the answer needs to be :)

- anonymous

no its all correct

- amistre64

y = -2(0) - 7
y = -7

- anonymous

its jst that they are on top of eachother .

- amistre64

lets see if these answers work;
-3(0)-2(-7)=14
0+14=14

- anonymous

14=14

- amistre64

2x+y = -7
2(0) + -7 = -7
0 +-7 = -7
-7=-7

- anonymous

correct.

- amistre64

so we have the correct solution; but what are your answer to choose from look like?

- anonymous

(-4,-1) (4,1) (-4,1) (4,-1)

- amistre64

....... then either those go to a different problem; or they are simply wrong :)

- anonymous

i think they are wrong but idk.

- amistre64

there can only be one solution to lines that cross; it is the point we found (0,-7)

- anonymous

the problem is correct

- anonymous

ok well thanks.:)

- amistre64

if you ahve a teacher, bring it to their attention :)

- anonymous

yes i will do that

- amistre64

tag!!

- anonymous

Stop that.

- amistre64

lol tag

- anonymous

Really really annoying.

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