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anonymous
 5 years ago
suppose f(x)= x^4 +ax^2. What is the value of a if f has a local min at x=2?
anonymous
 5 years ago
suppose f(x)= x^4 +ax^2. What is the value of a if f has a local min at x=2?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0suppose . [f(x)=x^{4}+ax ^{2.}\] What is the value of a if f has a local min at x=2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not sure if im supposed to find the derivative then set x = 2 then solve for a or something else..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If there is a local min at x=2, then f'(2)=0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If it has a local min, then we know the derivative at that point must be 0. So take the derivative, set x = 2, and set the derivative =0, then solve for a.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which is essentially what Xavier said, but with more words ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, i did that.. the answer is 8 but i got 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you get 4x^3+2ax=0 as the derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Substitute x=2 4(2)^2+4a=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank soo much. im stupid..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Everyone has those moments :P
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