anonymous
  • anonymous
suppose f(x)= x^4 +ax^2. What is the value of a if f has a local min at x=2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
suppose . [f(x)=x^{4}+ax ^{2.}\] What is the value of a if f has a local min at x=2?
anonymous
  • anonymous
im not sure if im supposed to find the derivative then set x = 2 then solve for a or something else..
anonymous
  • anonymous
If there is a local min at x=2, then f'(2)=0.

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More answers

anonymous
  • anonymous
If it has a local min, then we know the derivative at that point must be 0. So take the derivative, set x = 2, and set the derivative =0, then solve for a.
anonymous
  • anonymous
Which is essentially what Xavier said, but with more words ;p
anonymous
  • anonymous
okay, i did that.. the answer is -8 but i got -4
anonymous
  • anonymous
Did you get 4x^3+2ax=0 as the derivative?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Substitute x=2 4(2)^2+4a=0
anonymous
  • anonymous
4(2)^3+4a=0 I mean
anonymous
  • anonymous
it would be 4(2)^3
anonymous
  • anonymous
yeah
anonymous
  • anonymous
4a=-32
anonymous
  • anonymous
ohhh. okay. wow.
anonymous
  • anonymous
thank soo much. im stupid..
anonymous
  • anonymous
Everyone has those moments :P
amistre64
  • amistre64
tag!!
amistre64
  • amistre64
tag

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