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anonymous
 5 years ago
Which of the following is not a possible value for a probability?
A. 95%
B. 0.05
C. .999999999
D. 0
E. 11.05
anonymous
 5 years ago
Which of the following is not a possible value for a probability? A. 95% B. 0.05 C. .999999999 D. 0 E. 11.05

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0E. Probability can't be greater than 1 or 100%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk , this help seriously !!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The sum of all the probabilities in a sample space must equal 1, and none of them can have negative possibility (that doesn't make sense). Therefore none of them can have a probability greater than 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If two dice are rolled, what is the probability of getting two numbers greater than 4?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 numbers added higher than 4? or 2 faces that are higher than 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is the probability for 1 die getting a number greater than 4?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 numbers implies die faces I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Assume fair 6 sided dice. Then the numbers greater than 4 are 5 and 6. Since dice are independent. P(A and B)=P(A)*P(B)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02/6 = 1/3. To get 2 dice with each having a number greater than 4 you'd multiply the probability of each one together by the product rule.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 faces out of 6 are higher than 4; so if I see it right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Two independent outcome occurring here so as Xavier said you have P(A and B) = P(A)*P(B)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right? If each one has a 1/3 chance, having two at the same time would be \(\frac{1}{3}*\frac{1}{3} = \frac{1}{9}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Seriously.. it's just annoying.
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