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anonymous

  • 5 years ago

Which of the following is not a possible value for a probability? A. 95% B. 0.05 C. .999999999 D. 0 E. 11.05

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  1. anonymous
    • 5 years ago
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    E. Probability can't be greater than 1 or 100%

  2. anonymous
    • 5 years ago
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    idk , this help seriously !!

  3. amistre64
    • 5 years ago
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    tag!! running a test

  4. anonymous
    • 5 years ago
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    uqqh .

  5. anonymous
    • 5 years ago
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    The sum of all the probabilities in a sample space must equal 1, and none of them can have negative possibility (that doesn't make sense). Therefore none of them can have a probability greater than 1.

  6. anonymous
    • 5 years ago
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    If two dice are rolled, what is the probability of getting two numbers greater than 4?

  7. amistre64
    • 5 years ago
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    4out of 12

  8. anonymous
    • 5 years ago
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    wouldnt it be 1/36

  9. amistre64
    • 5 years ago
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    2 numbers added higher than 4? or 2 faces that are higher than 4?

  10. anonymous
    • 5 years ago
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    What is the probability for 1 die getting a number greater than 4?

  11. amistre64
    • 5 years ago
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    2 numbers implies die faces I think

  12. anonymous
    • 5 years ago
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    Assume fair 6 sided dice. Then the numbers greater than 4 are 5 and 6. Since dice are independent. P(A and B)=P(A)*P(B)

  13. anonymous
    • 5 years ago
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    2/6 = 1/3. To get 2 dice with each having a number greater than 4 you'd multiply the probability of each one together by the product rule.

  14. anonymous
    • 5 years ago
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    1/3

  15. amistre64
    • 5 years ago
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    2 faces out of 6 are higher than 4; so if I see it right

  16. anonymous
    • 5 years ago
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    Two independent outcome occurring here so as Xavier said you have P(A and B) = P(A)*P(B)

  17. anonymous
    • 5 years ago
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    Right? If each one has a 1/3 chance, having two at the same time would be \(\frac{1}{3}*\frac{1}{3} = \frac{1}{9}\)

  18. amistre64
    • 5 years ago
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    tag

  19. anonymous
    • 5 years ago
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    Seriously.. it's just annoying.

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