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anonymous

  • 5 years ago

how do you find the equation for a graph with x-intercepts of (2,0) and (-6,0) and a maximum point of (-2,4)

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  1. amistre64
    • 5 years ago
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    thats a quadratic

  2. amistre64
    • 5 years ago
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    the most basic approach is to solve for 3 equations with variables of a b and c; using your x and y values as your quadratic constants

  3. amistre64
    • 5 years ago
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    or...or factor in the roots

  4. amistre64
    • 5 years ago
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    (x-2)(x+6)

  5. amistre64
    • 5 years ago
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    C(x^2 +4x -12) is the family of quadratics with these roots

  6. amistre64
    • 5 years ago
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    if we complete the square and plug in for the vertex we got it solved

  7. amistre64
    • 5 years ago
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    x^2 +4x +4 = 12+4 (x+2)^2 = 16

  8. amistre64
    • 5 years ago
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    (-1/4)(x+2)^2 +4 = y might be it

  9. amistre64
    • 5 years ago
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    lets check it out :)

  10. amistre64
    • 5 years ago
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    -1/4(x^2 +4x-12) -x^2/4 -x +3 1/2(-1/4) = 1/(-2/4) = 1/(-1/2) = -2 x is good

  11. amistre64
    • 5 years ago
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    -1/4(x^2 +4x -12) |x=-2 (-1/4)(4 -8 -12) = -16/-4 = 4 YES

  12. amistre64
    • 5 years ago
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    now that I taught mysef something, any questions lol

  13. anonymous
    • 5 years ago
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    no

  14. amistre64
    • 5 years ago
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    :) good, cause I dont know if I can remember how I did it ;)

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