A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
find a quadratic function given by f(x)=a(xh)^2+k that models the data 1940,0.25,1968,1.60,1997,5.15 need help solving for a
anonymous
 5 years ago
find a quadratic function given by f(x)=a(xh)^2+k that models the data 1940,0.25,1968,1.60,1997,5.15 need help solving for a

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ack!! not this one again..I got a program for this ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i programmed this just for cases like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me solve for a

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.10.001301745743669519x^2 5.0390080805461945x + 4876.675395385017

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a = something like 64.24/48957 or some rediculaous monster of a fraction

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you wanna know the min wage of 1976 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so when i re write the equation it will look like f(x)= a(x1940)^2+0.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you can write the equation to be a(x40)^2 to make the numbers easier yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so which of the numbers would i put in for a being that i have to show steps

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if we adjust in my program for the 40 we get this: 0.0013017457436695185(x40)^2 + 0.011765404891539196(x40) + 0.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ive got a post about this same thing a couple of days ago that I typed it all out :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'd use y=ax^2+bx+c. They give you values for x and y. Like: 0.25=a(1940)^2+b(1940)+c If you use the three coordinates like that. You will have a system of equations in three variables. Solve for a, b and c. Then complete the square to get it back in vertex form which will probably be a pain.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1id have to redo it all, its a monster tho....here goes :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a(19401940)^2 + b(19401940) + c = .25 from this we see that c = .25 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1im gonna write it as the lesser numbers instead of the years ok? just be easier...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the other 2 equations then are: a(28)^2 +b(28) + .25 = 1.60 a(57)^2 +b(57) + .25 = 5.15

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1solve for a I suppose is as likely as any other...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a = 1.60  .25 b(28)  now use this value in the other one (28)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1write down that value for a, your gonna need it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a(57^2) + b(57) = 5.15  .25 (57^2)(1.60  .25 b(28)  + b(57) = 4.60 (28)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(57^2)(1.35) b(57^2)(28) + b(57)(28^2) = 4.60(28^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1b[(57^2)(28) + (57)(28^2)] = 4.60(28^2)  57^2(1.35)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14.60(28^2)  57^2(1.35) b = ; thats b lol (57)(28^2)  (57^2)(28)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a = 1.60  .25 b(28)  ; now plug the value of b into this spot (28)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.13606.40  4386.15  = b 44688  90972

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1b = 0.016847074583009247256071212514044 if I kept track of it... compare that to the one I posted earlier

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1+ 0.011765404891539196; this ones better, I probably missed something earlier....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1but if you must show your work, its just a matter of grunging your way thru it..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1The grunge work is this; formula i worked out ((p1p2)*((n3*n3)(n1*n1))+(p3p1)*((n2*n2)(n1*n1)))  (((n3*n3)(n1*n1))*(n1n2)+((n2*n2)(n1*n1))*(n3n1))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1n1 = year1 ; p1 = pay1 and the rest is after this manner

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol. Parentheses fun. I always like seeing things solved for variables though.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{[(p1p2)]*[(n3^2)(n1^2)]+[(p3p1)]*[(n2^2)(n1^2)]}{[(n3^2)(n1^2)]*[(n1n2)]+[(n2^2)(n1^2)]*[(n3n1)]}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you also wanna know when it was near $1 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11959 is under a 1 and 1960 is a little over 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1any questions yet? ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(p2p1) (n2n1)*b a =    (n2^2)(n1^2) (n2^2)(n1^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(p2p1)  (n2n1)*b a =  is just as good (n2^2)(n1^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so this was the formula that i used to determine when minimum wage was 1.00 is this correct y=1.00(19641940)^2+.25 y=1.00*234^2+.25 y=(1.00*.576)+.25 y=.58+.25=1.08

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no, thats not correct minwage = y = 1 $1 is not a constant for the equation; it is a solution to it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and you are missing your middle term

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you would take $1 from c(.25) setting the whole equation = 0; then use the quadratic formula to calculate roots as solutions and throw out the obvious wrong one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so could you show me how to write the equation and i try to solve it again

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or trial and error it like I did ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lets do this the generic way to get you to the formula I alrady created; and then all you need to do is fill in the plugs.... ok? thatll save a whole lot of little numbers getting orphaned :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = year and p = price; makes sense? a(y1)^2 + b(y1) + c = (p1)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a(y1)^2 + b(y1) + c = (p1) Eq1 a(y2)^2 + b(y2) + c = (p2) Eq2 a(y3)^2 + b(y3) + c = (p3) Eq3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1eq1; c = (p1) b(y1)  a(y1)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1laptop cord got unplugged lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Eq ; a(y2)^2 + b(y2) + c = (p2) a(y2)^2 + b(y2) + (p1) b(y1)  a(y1)^2 = (p2) [a(y2)^2  a(y1)^2] + [b(y2) b(y1)] = (p2)  (p1) a[(y2)^2 (y1)^2] + b[(y2) (y1)] = (p2)  (p1) a = (p2)  (p1)  [(y2) (y1)]b  [(y2)^2 (y1)^2] thats what a equals a[(y2)^2 (y1)^2] = (p2)  (p1)  [(y2) (y1)]b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1forget that last part, its seems a bit spurious.... forgot to delete it lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1From Eq3 we substitute all the values if for a and c a(y3)^2 + b(y3) + c = (p3) (y3^2) [(p2)  (p1)  [(y2) (y1)]b  [(y2)^2 (y1)^2] + b(y3) + (p1) b(y1)  [(y1)^2](y3^2) [(p2)  (p1)  [(y2) (y1)]b  [(y2)^2 (y1)^2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we end up solving this for b and the plugging in the values that I already postd for B above :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you feel up to all that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have to be up to it lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1I posted all the formulas; start with b go to a and then...well c is .25 for this one lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1B = (.251.60) [(57^2)(28^2)]+(5.15.25)[(28^2)(0^2)]  (0 28)[(57^2)(28^2)]+(5728)[(28^2)(0^2)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok this is how i did it lol(b) I believe that the quadratic function that models the data is y = a (y  1940)2 + .25 because it seems right. (c) Estimate the minimum wage in 1976 and compare it to the actual value of $2.30. y = $1.99 (1976 – 1940)2 + .25 y = $1.99 · 362 + .25 y = ($1.99 · 1296) + .25 y = $2.58 + .25 = $2.83 Estimated $2.83 (d) Estimate when the minimum wage was $1.00. y = $1.00 (1964 – 1940)2 + .25 y = $1.00 · 242 + .25 y = ($1.00 · 576) + .25 y = $.58 + .25 = $1.08 The year 1964 (e) If current trends continue, predict the minimum wage in 2009. Compare it to the projected value of $7.25. y = $7.25 (2009 – 1940)2 + .25 y = $7.25 · 692 + .25 y = ($7.25 · 4761) + .25 y = $3.45 + .25 = $3.70 Minimum wage $3.70 @ a $3.55 difference

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i might have jacked it up sorry

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1If it works for you use it ;) but dont use y for year and y for a dependant variable, its confusing lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the way you solve for it depends on the degree of accuracy you are looking for.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so take y out? do i do them correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did i do them correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1I dont know how you did them ;) but you shouldnt use y to mean year AND y to mean value of the function....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1my way gives me 7.259 for min wage in 2007

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1compared to 7.25 thats pretty accurate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so i re did equation F (0) = .25 (0 1.60)^2 + 5.15 .25(1.60)^2 + 5.15 .25(2.56) + 5.15 .64 +5.15

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i dont understand the process of how you get your equation; im sure it has to do with homogeneous difference equattions tho...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the only way I know how to solce for quadratics with three data points is to plug them into the quad equation and solve for a b and c

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and that aint what you did there :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay lets scratch last equation lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1do you know how to solve for a system of equations?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1c= .25 a(28^2) + b(28) + c = 1.60 a(58^2) + b(58) + c = 5.15 solve by substitution, elimination or matrix....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a(28^2) + b(28) = 1.60.25 = 1.35 a(58^2) + b(58) = 5.15.25 = 4.90 a(28^2) + b(28) = 1.35 a = [1.35  b(28)]/(28^2) ...................................... a(58^2) + b(58) = 4.90 ; plug in value for a

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(58^2)[1.35  b(28)] + b(58)(28^2) = 4.90(28^2) 58^2(1.35) b(58^2)(28) + b(58)(28^2) = 4.90(28^2) b[(58^2)(28) +(58)(28^2)] = 4.90(28^2)  58^2(1.35) b = 4.90(28^2)  58^2(1.35)  (58^2)(28) +(58)(28^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1plug those numbers into a calculator to get the solid value for 'b' and use it in the equation above it to solve for 'a'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1((4.90 * (28^2))  ((58^2) * 1.35)) / ((((58^2)) * 28) + (58 * (28^2))) = 0.014363711 Google says b = .014363711

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a = [1.35  b(28)]/(28^2) (1.35  (.014363711 * 28)) / (28^2) = 0.0012089491
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.