anonymous
  • anonymous
What's the derivative of f(x)= xe^-x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
i am pretty sure you can only break that down using ln
anonymous
  • anonymous
No need to use ln. You have to use the product rule.
anonymous
  • anonymous
Yes product rule, but is it necessary to do ln AnwarA. I don't think so, it is a form we can handle.

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anonymous
  • anonymous
\[f'(x)=x(-2xe ^{-x^2})+e ^{-x^2}\]
anonymous
  • anonymous
Simplify, you will get: \[f'(x)=e ^{-x^2}(1-2x^2)\]
anonymous
  • anonymous
Does that makes sense?
anonymous
  • anonymous
I"m not sure how you simplified
anonymous
  • anonymous
Well. I took e^(-x^2) as a common factor, and multiplied (-2x)(x)=-2x^2.
anonymous
  • anonymous
oh! That makes sense :)
anonymous
  • anonymous
Are you aware of the product rule? Can you use it?
anonymous
  • anonymous
Yes. Thanks so much for your help!
anonymous
  • anonymous
You're most welcome!!
anonymous
  • anonymous
Have a great day!

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