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anonymous

  • 5 years ago

What's the derivative of f(x)= xe^-x^2

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  1. anonymous
    • 5 years ago
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    i am pretty sure you can only break that down using ln

  2. anonymous
    • 5 years ago
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    No need to use ln. You have to use the product rule.

  3. anonymous
    • 5 years ago
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    Yes product rule, but is it necessary to do ln AnwarA. I don't think so, it is a form we can handle.

  4. anonymous
    • 5 years ago
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    \[f'(x)=x(-2xe ^{-x^2})+e ^{-x^2}\]

  5. anonymous
    • 5 years ago
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    Simplify, you will get: \[f'(x)=e ^{-x^2}(1-2x^2)\]

  6. anonymous
    • 5 years ago
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    Does that makes sense?

  7. anonymous
    • 5 years ago
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    I"m not sure how you simplified

  8. anonymous
    • 5 years ago
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    Well. I took e^(-x^2) as a common factor, and multiplied (-2x)(x)=-2x^2.

  9. anonymous
    • 5 years ago
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    oh! That makes sense :)

  10. anonymous
    • 5 years ago
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    Are you aware of the product rule? Can you use it?

  11. anonymous
    • 5 years ago
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    Yes. Thanks so much for your help!

  12. anonymous
    • 5 years ago
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    You're most welcome!!

  13. anonymous
    • 5 years ago
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    Have a great day!

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