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anonymous
 5 years ago
solve the compound inequality
5>3x+4 or 10≤5x+4
anonymous
 5 years ago
solve the compound inequality 5>3x+4 or 10≤5x+4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does the following look about right? \[x\leq \frac{6} {5}\x>\frac{1}{3} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does the following look about right? \[x\leq \frac{6} {5}\x>\frac{1}{3} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it infinity 1/3 or 1/3 infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well the result is from executing Reduce[5>3x+4 or 10≤5x+4,x] in Mathematica. Have not solved inequalities manually for decades. Not sure where infinity figures into this problem. Is this your question or did someone else put you up to it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is my question from algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is multiple choice and one of the answers looks like this (005/6) upside down u (1/3 00)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 00 are infinity signs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Looking back at the answer I would guess that 1/3 infinity is the answer because x has to be greater than .033333 all the way to infinity if desired.
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