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anonymous
 5 years ago
Another more specific question: In Module 3 in the course notes (p.225) is written that “Notice the discontinuity in electric field as we cross the plane. The discontinuity is given ...then the normal component of the electric field across that surface always exhibits a discontinuity with ΔEn=σ/ε0”. Could someone explain this please?
anonymous
 5 years ago
Another more specific question: In Module 3 in the course notes (p.225) is written that “Notice the discontinuity in electric field as we cross the plane. The discontinuity is given ...then the normal component of the electric field across that surface always exhibits a discontinuity with ΔEn=σ/ε0”. Could someone explain this please?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The charge lies in a plane where z = 0 (the xy plane) Above the plane, in the positive z region, the electric field points away from positive charge, and so will be in the positivez direction (if the sheet of charge is positive). On the other side of the plane of charge, in the negative z region, the electric field also points away from positive charge, and so must point in the negative z direction (if the sheet of charge is positive). That means that the electric field must go from pointing in the positive z direction just above the sheet of charge to pointing in the negative z direction just below the sheet of charge  that's a discontinuity. The notes show how the magnitude of the field was calculated (\[\sigma/2\epsilon _{0}\]) just above and below, but opposite in sign (direction) so that the total change in E is \[\sigma/\epsilon _{0}\]
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