Tell weather the graph opens up or down
Identify the vertx
tell if the graph is wider or narrower or the same as the graph of Y =|X|
f(x)=2| x+2| +8

- anonymous

- schrodinger

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- anonymous

You know how translating functions works right?

- anonymous

no.

- anonymous

xavier can you help me please

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## More answers

- anonymous

Well what you add to the x is how many units the function is moves to the left. What you add outside is how many units up. So f(x)=2|x-h|+k has been moves h to the right and k up. Since the vertex was originally at (0,0) its not at (h,k)

- anonymous

now at (h,k)

- anonymous

so the vertex is 0,0

- anonymous

Its originally (0,0) on the graph y=|x| but since you did that stuff to it, it moved to (h,k) where f(x)=2|x-h|+k. In this case h=-2 and k=8 so the vertex is at (-2,8)

- anonymous

okay does it open up or down and is it narrow or wider

- anonymous

If the number in front of the absolute value is positive, then it opens up. If negative it opens down.
If the absolute value of that number is greater than 1, then its narrower. If the absolute value is less than 1, then its wider.

- anonymous

so its narrower :)

- anonymous

Right?

- anonymous

Yeah. How about the way it opens?

- anonymous

it opens up?

- anonymous

Yup. :)

- anonymous

can you do another one for me ?

- anonymous

Sure but lets see how far you can get first before I help. Look over how we did this one

- anonymous

f(x)=7|x-3|-4

- anonymous

okay so i think it open up

- anonymous

and the x=3 but i can tfind the second number

- anonymous

f(x)=a|x-h|+k. Remember vertex is at (h,k)

- anonymous

yes and h=3 right?

- anonymous

Yeah

- anonymous

but i cant find k i think its 1 but idk

- anonymous

You have
f(x)=7|x-3|-4
f(x)=a|x-h|+k
Look at the placement of the letters.

- anonymous

-4 is k?

- anonymous

Yeah.

- anonymous

okay so the vertex is 3,-4

- anonymous

and it opens up and its narrower

- anonymous

Yup you got it

- anonymous

everything is right?

- anonymous

Yeah

- anonymous

yesss thank you so much :)

- anonymous

Np

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