what is a solution for the equation 2^n=10?

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what is a solution for the equation 2^n=10?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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http://www.wolframalpha.com/input/?i=2^n+%3D10
Did you try taking the square root?
Margaret?

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Other answers:

Am I missing something? Why would you take the square root... ?
To get the value of n that yields 10.
take the square root and then..? it doesnt work
Ack! dislexia
Don't worry, your answer was still more helpful than Mr. Wolfram's
Take the log
im confused
I read it as \(n^2\) not \(2^n\) I need my exponents small and above, that flat representation plays hell with my dislexia.
Take the log of both sides.
Take the logarithm of both sides (ln or log for calc friendly) to knock that n down.
log10 right?
Log is much more friendly since it's a 10 on the other side
But any log will do.
would the answer be.. n=10/log2?
No, you forgot to take the log of 10 also.
soo.. n=1/log2?
I wish that in addition to medals they'd let us award slaps for people who give half-assed answers and wander off ;p
Yes precisely!
so i got it!!?? :)
You did! =)
thankyou for your help
You're very welcome.

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