anonymous
  • anonymous
what is a solution for the equation 2^n=10?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=2^n+%3D10
anonymous
  • anonymous
Did you try taking the square root?
anonymous
  • anonymous
Margaret?

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More answers

anonymous
  • anonymous
Am I missing something? Why would you take the square root... ?
anonymous
  • anonymous
To get the value of n that yields 10.
anonymous
  • anonymous
take the square root and then..? it doesnt work
anonymous
  • anonymous
Ack! dislexia
anonymous
  • anonymous
Don't worry, your answer was still more helpful than Mr. Wolfram's
anonymous
  • anonymous
Take the log
anonymous
  • anonymous
im confused
anonymous
  • anonymous
I read it as \(n^2\) not \(2^n\) I need my exponents small and above, that flat representation plays hell with my dislexia.
anonymous
  • anonymous
Take the log of both sides.
anonymous
  • anonymous
Take the logarithm of both sides (ln or log for calc friendly) to knock that n down.
amistre64
  • amistre64
log10 right?
anonymous
  • anonymous
Log is much more friendly since it's a 10 on the other side
anonymous
  • anonymous
But any log will do.
anonymous
  • anonymous
would the answer be.. n=10/log2?
anonymous
  • anonymous
No, you forgot to take the log of 10 also.
anonymous
  • anonymous
soo.. n=1/log2?
anonymous
  • anonymous
I wish that in addition to medals they'd let us award slaps for people who give half-assed answers and wander off ;p
anonymous
  • anonymous
Yes precisely!
anonymous
  • anonymous
so i got it!!?? :)
anonymous
  • anonymous
You did! =)
anonymous
  • anonymous
thankyou for your help
anonymous
  • anonymous
You're very welcome.

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