solve for x: 2^x+1=8^x-2

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solve for x: 2^x+1=8^x-2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Is that 2^(x+1)?
yes
Note you can write 8 as 2^3. Try using that

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Other answers:

so x=3/2?
No. How did you come to that answer?
reducing? im really not good at math
So we can substitute 2^3 for 8 right. It becomes 2^(x+1)=[2^3]^(x-2). The right hand side can be simplified 2^(x+1)=2^3(x-2) Since the bases are the same, the exponents must be equal.
x would = 2
Did you equate the exponents: Like if i say a^x=a^y, x must be equal to y. So in our case x+1=3(x-2)
x=7/2?
Yes. Do you see how the substitution helped? It made the bases the same so we can conclude that the exponents are equal
yes you smart cookie. thankyou!!
:) Np

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