anonymous
  • anonymous
solve for x: 2^x+1=8^x-2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Is that 2^(x+1)?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Note you can write 8 as 2^3. Try using that

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anonymous
  • anonymous
so x=3/2?
anonymous
  • anonymous
No. How did you come to that answer?
anonymous
  • anonymous
reducing? im really not good at math
anonymous
  • anonymous
So we can substitute 2^3 for 8 right. It becomes 2^(x+1)=[2^3]^(x-2). The right hand side can be simplified 2^(x+1)=2^3(x-2) Since the bases are the same, the exponents must be equal.
anonymous
  • anonymous
x would = 2
anonymous
  • anonymous
Did you equate the exponents: Like if i say a^x=a^y, x must be equal to y. So in our case x+1=3(x-2)
anonymous
  • anonymous
x=7/2?
anonymous
  • anonymous
Yes. Do you see how the substitution helped? It made the bases the same so we can conclude that the exponents are equal
anonymous
  • anonymous
yes you smart cookie. thankyou!!
anonymous
  • anonymous
:) Np

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